Jawaban:

D. 2

Penjelasan dengan langkah-langkah:

F ( x-1 ) = x + 2

<=>

Dimisalkan : y = x - 1, maka :

x = y + 1

F (y) = x + 2

F (x) = F (y) + 1

F (x) = ( x + 2) + 1

F (x) = x + 3

<=>

Dimisalkan

y = ( 2 - x) / ( x + 3)

y ( x + 3) = ( 2 - x)

x y + 3 y = 2 - x

xy + y = 2 - 3 y

x ( y + 1) = 2 - 3 y

x = ( 2 - 3 y) / ( 1 + y)

<=>

Didapat kan

g–¹ (x), = ( 2 - 3 x) / ( + x)

( g–¹ o f ) (x) = ( 2 - 3. ( [ f ( x) ] ) / ( 1 + f [x] )

( g–¹ of ) (x) = ( 2 - 3 [x + 3 ] ) / ( 1 + [ x + 3 ] )

maka

( g–¹ of) (x) = ( 2- 3. x ] ) / ( x + 4 )

( g –¹ of) (x) = ( - 3 x x - 7) / ( x + 4)

maka

( g–¹ of) (1) = ( - 3.[1] - 7) / ( [1] + 4)

(g–¹ of) (1) = ( - 10) / (5)

g–¹of) (1) = 2