Q. BY => Me :v _[tex] \sf {50}^{3} +

Berikut ini adalah pertanyaan dari CalmeLidia01 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Pertama

Q. BY => Me :v

_

 \sf {50}^{3} + {20}^{3} =
_

;-;​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Pendahuluan :

\tt \color{red}{Bilangan \: Berpangkat }

Bilangan berpangkat adalah perkalian berulang-ulang dengan bilangan yang sama sebanyak pangkatnya. Nama lain bilangan berpangkat adalah eksponen. bentuk umum bilangan berpangkat dinyatakan sebagai aⁿ (dibaca a pangkat n), dimana a dikalikan sebanyak n.

\tt \color{pink}{♣Bentuk \: Umum :}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \pink{ \sf {a}^{n} = \sf \underbrace{ \: a \times a \times a \times ... \times a \times a}} \\ \pink{\sf {}^{ \: \: \: \: \: \: \: \: sebanyak \: n \: faktor} }\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

\tt \color{yellow}{♣Contoh ~ Perpangkatan :}

\sf {1}^{1} = 1 × 1 = 1

\sf {2}^{2} = 2 \times 2 = 4

\sf {3}^{2} = 3 \times 3 = 9

\sf{4}^{2} = 4 \times 4 = 16

\sf {5}^{2} = 5 \times 5 = 25

\sf {6}^{2} = 6 \times 6 = 36

\sf {7}^{2} = 7 \times 7 = 49

\sf {8}^{2} = 8 \times 8 = 64

\sf {9}^{2} = 9 \times 9 = 81

\sf {10}^{2} = 10 \times 10 = 100

\sf {11}^{2} = 11 \times 11 = 121

\sf {12}^{2} = 12 \times 12 = 144

\sf {13}^{2} = 13 \times 13 = 169

\sf {14}^{2} = 14 \times 14 = 196

\sf {15}^{2} = 15 \times 15 = 225

\sf {16}^{2} = 16 \times 16= 256

\sf {17}^{2} = 17 \times 17 = 289

\sf {18}^{2} = 18 \times 18 = 324

\sf {19}^{2} = 19 \times 19 = 361

\sf {20}^{2} = 20 \times 20 = 400

\tt \color{red}{♣Contoh ~ Perpangkatan \: menyederhanakan :}

15² × 15² =

= 15^(2 + 2)

= 15⁴

= 15 × 15 × 15 × 15

= 225 × 15 × 15

= 3.375 × 15

= 50.625

- - - - - - - - - - - - - - - -

\tt \color{yellow}{♣Cara ~ Mencari ~ Nilai ~ Perpangkatan ~ 2 :}

A² = A × A

C² = U × U

V² = V × V

\tt \color{red}{♣Cara ~ Mencari ~ Nilai ~ Perpangkatan ~ 3 :}

K³ = K × K × K

Z³ = Z × Z × Z

B³ = D × D × D

- - - - - - - - - - - - - - - - --

\tt \color{blue}{♣Sifat-sifat ~ Perpangkatan:}♣Sifat−sifat Perpangkatan:[tex]\sf {a}^{n} \times {a}^{m} = {a}^{n + m}

  • \sf {a}^{m} \div {a}^{n} = {a}^{m - n}
  • \sf( {a}^{n} ) {}^{m} = {a}^{n \times m}
  • \sf {(a \times b)}^{n} = {a}^{n} \times {b}^{n}
  • \sf {(a \div b)}^{m} = \frac{ {a}^{m} }{ {b}^{m} }
  • \sf \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} }
  • \sf {a}^{0} = 1
  • \sf {a}^{1} = a
  • - - - - - - - - - - - - - - - - -

    \tt \color{red}{♣Contoh ~ Perpangkatan ~ 2 :}

    1² = 1 × 1 = 1

    2² = 2 × 2 = 4

    3² = 3 × 3 = 9

    4² = 4 × 4 = 16

    5² = 5 × 5 = 25

    6² = 6 × 6 = 36

    7² = 7 × 7 = 49

    8² = 8 × 8 = 64

    9² = 9 × 9 = 81

    10² = 10 × 10 = 100

    \tt \color{red}{♣Contoh ~ Perpangkatan ~ 3 :}

    1³ = 1 × 1 × 1 = 1

    2³ = 2 × 2 × 2 = 8

    3³ = 3 × 3 × 3 = 27

    4³ = 4 × 4 × 4 = 64

    5³ = 5 × 5 × 5 = 124

    6³ = 6 × 6 × 6 = 216

    7³ = 7 × 7 × 7 = 343

    8³ = 8 × 8 × 8 = 512

    9³ = 9 × 9 × 9 = 729

    10³ = 10 × 10 × 10 = 1.000

    \tt \color{red}{♣Contoh ~ Perpangkatan ~ 4 :}

    1³ = 1 × 1 × 1 × 1 = 4

    2⁴ = 2 × 2 × 2 × 2 = 16

    3⁴ = 3 × 3 × 3 × 3 = 81

    4⁴ = 4 × 4 × 4 × 4 = 256

    5⁴ = 5 × 5 × 5 × 5 = 625

    6⁴ = 6 × 6 × 6 × 6 = 1.296

    7⁴ = 7 × 7 × 7 × 7 = 2.401

    8⁴ = 8 × 8 × 8 × 8 = 4.096

    9⁴ = 9 × 9 × 9 × 9 = = 6.561

    10⁴ = 10 × 10 × 10 × 10 = 10.000

    \tt \color{red}{♣Contoh ~ Perpangkatan ~ 5 :}

    1⁵ = 1 × 1 × 1 × 1 × 1 = 1

    2⁵ = 2 × 2 × 2 × 2 × 2 = 32

    3⁵ = 3 × 3 × 3 × 3 × 3 = 243

    4⁵ = 4 × 4 × 4 × 4 × 4 = 1.024

    5⁵ = 5 × 5 × 5 × 5 × 5 = 3.125

    6⁵ = 6 × 6 × 6 × 6 × 6 = 7.776

    7⁵ = 7 × 7 × 7 × 7 × 7 = 16.807

    8⁵ = 8 × 8 × 8 × 8 × 8 = 32.768

    9⁵ = 9 × 9 × 9 × 9 × 9 = 59.049

    10⁵ = 10 × 10 × 10 × 10 × 10 = 100.000

    Pembahasan =

    \tt {50}^{3} + {20}^{3} =

    \tt = (50 \times 50 \times 50) + (20 \times 20 \times 20)

    \tt = (2.500 \times 50) + (400 \times 20)

    \tt = 125.000 + 8.000

    \tt = 133.000

    { \color{lavender}{ \underbrace{ \huge{ \bold{ \color{red}{Learn \ More}}}}}}

    { \color{lavender}{ \underbrace{ \huge{ \bold{ \color{skyblue}{Detail \ Jawaban }}}}}}

    • Kelas : 9
    • Tingkat : Sekolah Menengah Pertama ( SMP )
    • Mapel : Math
    • Bab : 1
    • Materi = Bilangan Berpangkat
    • Kode Mapel : 2
    • Kode Kategorisasi : 9.2.1
    • Kata kunci = Hasil dari bilangan berpangkat 50³ + 20³

    \huge\tt\color{FF6666}{@Mo}\color{FFB266}{c}\color{B2FF66}{hii}\color{66FF66}{k}\color{66FFFF}{u}\color{66B2FF}{u}\color{6666FF}{}\color{B266FF}{}\color{FF66FF}{}\color{FF66B2}{} \color{FF9999}{}\color{FFCC99}

    Pendahuluan :[tex]\tt \color{red}{Bilangan \: Berpangkat }[/tex]Bilangan berpangkat adalah perkalian berulang-ulang dengan bilangan yang sama sebanyak pangkatnya. Nama lain bilangan berpangkat adalah eksponen. bentuk umum bilangan berpangkat dinyatakan sebagai aⁿ (dibaca a pangkat n), dimana a dikalikan sebanyak n.[tex]\tt \color{pink}{♣Bentuk \: Umum :}[/tex][tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \pink{ \sf {a}^{n} = \sf \underbrace{ \: a \times a \times a \times ... \times a \times a}} \\ \pink{\sf {}^{ \: \: \: \: \: \: \: \: sebanyak \: n \: faktor} }\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex] [tex]\tt \color{yellow}{♣Contoh ~ Perpangkatan :}[/tex][tex]\sf {1}^{1} = 1 × 1 = 1[/tex][tex]\sf {2}^{2} = 2 \times 2 = 4[/tex][tex]\sf {3}^{2} = 3 \times 3 = 9[/tex][tex]\sf{4}^{2} = 4 \times 4 = 16[/tex][tex]\sf {5}^{2} = 5 \times 5 = 25[/tex][tex]\sf {6}^{2} = 6 \times 6 = 36[/tex][tex]\sf {7}^{2} = 7 \times 7 = 49[/tex][tex]\sf {8}^{2} = 8 \times 8 = 64[/tex][tex]\sf {9}^{2} = 9 \times 9 = 81[/tex][tex]\sf {10}^{2} = 10 \times 10 = 100[/tex][tex]\sf {11}^{2} = 11 \times 11 = 121[/tex][tex]\sf {12}^{2} = 12 \times 12 = 144[/tex][tex]\sf {13}^{2} = 13 \times 13 = 169[/tex][tex]\sf {14}^{2} = 14 \times 14 = 196[/tex][tex]\sf {15}^{2} = 15 \times 15 = 225[/tex][tex]\sf {16}^{2} = 16 \times 16= 256[/tex][tex]\sf {17}^{2} = 17 \times 17 = 289[/tex][tex]\sf {18}^{2} = 18 \times 18 = 324[/tex][tex]\sf {19}^{2} = 19 \times 19 = 361[/tex][tex]\sf {20}^{2} = 20 \times 20 = 400[/tex][tex]\tt \color{red}{♣Contoh ~ Perpangkatan \: menyederhanakan :}[/tex]15² × 15² == 15^(2 + 2)= 15⁴= 15 × 15 × 15 × 15= 225 × 15 × 15= 3.375 × 15= 50.625- - - - - - - - - - - - - - - -[tex]\tt \color{yellow}{♣Cara ~ Mencari ~ Nilai ~ Perpangkatan ~ 2 :}[/tex]A² = A × AC² = U × UV² = V × V[tex]\tt \color{red}{♣Cara ~ Mencari ~ Nilai ~ Perpangkatan ~ 3 :}[/tex]K³ = K × K × KZ³ = Z × Z × ZB³ = D × D × D- - - - - - - - - - - - - - - - --[tex]\tt \color{blue}{♣Sifat-sifat ~ Perpangkatan:}♣Sifat−sifat Perpangkatan:[tex]\sf {a}^{n} \times {a}^{m} = {a}^{n + m}[/tex][tex]\sf {a}^{m} \div {a}^{n} = {a}^{m - n}[/tex][tex]\sf( {a}^{n} ) {}^{m} = {a}^{n \times m}[/tex][tex]\sf {(a \times b)}^{n} = {a}^{n} \times {b}^{n}[/tex][tex]\sf {(a \div b)}^{m} = \frac{ {a}^{m} }{ {b}^{m} }[/tex][tex]\sf \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} }[/tex] [tex]\sf {a}^{0} = 1[/tex][tex]\sf {a}^{1} = a[/tex]- - - - - - - - - - - - - - - - -[tex]\tt \color{red}{♣Contoh ~ Perpangkatan ~ 2 :}[/tex]1² = 1 × 1 = 12² = 2 × 2 = 43² = 3 × 3 = 94² = 4 × 4 = 165² = 5 × 5 = 256² = 6 × 6 = 367² = 7 × 7 = 498² = 8 × 8 = 649² = 9 × 9 = 8110² = 10 × 10 = 100[tex]\tt \color{red}{♣Contoh ~ Perpangkatan ~ 3 :}[/tex]1³ = 1 × 1 × 1 = 12³ = 2 × 2 × 2 = 83³ = 3 × 3 × 3 = 274³ = 4 × 4 × 4 = 645³ = 5 × 5 × 5 = 1246³ = 6 × 6 × 6 = 2167³ = 7 × 7 × 7 = 3438³ = 8 × 8 × 8 = 5129³ = 9 × 9 × 9 = 72910³ = 10 × 10 × 10 = 1.000[tex]\tt \color{red}{♣Contoh ~ Perpangkatan ~ 4 :}[/tex]1³ = 1 × 1 × 1 × 1 = 42⁴ = 2 × 2 × 2 × 2 = 163⁴ = 3 × 3 × 3 × 3 = 814⁴ = 4 × 4 × 4 × 4 = 2565⁴ = 5 × 5 × 5 × 5 = 6256⁴ = 6 × 6 × 6 × 6 = 1.2967⁴ = 7 × 7 × 7 × 7 = 2.4018⁴ = 8 × 8 × 8 × 8 = 4.0969⁴ = 9 × 9 × 9 × 9 = = 6.56110⁴ = 10 × 10 × 10 × 10 = 10.000[tex]\tt \color{red}{♣Contoh ~ Perpangkatan ~ 5 :}[/tex]1⁵ = 1 × 1 × 1 × 1 × 1 = 12⁵ = 2 × 2 × 2 × 2 × 2 = 323⁵ = 3 × 3 × 3 × 3 × 3 = 2434⁵ = 4 × 4 × 4 × 4 × 4 = 1.0245⁵ = 5 × 5 × 5 × 5 × 5 = 3.1256⁵ = 6 × 6 × 6 × 6 × 6 = 7.7767⁵ = 7 × 7 × 7 × 7 × 7 = 16.8078⁵ = 8 × 8 × 8 × 8 × 8 = 32.7689⁵ = 9 × 9 × 9 × 9 × 9 = 59.04910⁵ = 10 × 10 × 10 × 10 × 10 = 100.000Pembahasan =[tex]\tt {50}^{3} + {20}^{3} = [/tex][tex]\tt = (50 \times 50 \times 50) + (20 \times 20 \times 20)[/tex][tex]\tt = (2.500 \times 50) + (400 \times 20)[/tex][tex]\tt = 125.000 + 8.000[/tex][tex]\tt = 133.000[/tex][tex]{ \color{lavender}{ \underbrace{ \huge{ \bold{ \color{red}{Learn \ More}}}}}}[/tex]https://brainly.co.id/tugas/47014842https://brainly.co.id/tugas/47013484https://brainly.co.id/tugas/46592229[tex]{ \color{lavender}{ \underbrace{ \huge{ \bold{ \color{skyblue}{Detail \ Jawaban }}}}}}[/tex]	Kelas : 9Tingkat : Sekolah Menengah Pertama ( SMP )Mapel : MathBab : 1Materi = Bilangan BerpangkatKode Mapel : 2Kode Kategorisasi : 9.2.1Kata kunci = Hasil dari bilangan berpangkat 50³ + 20³[tex]\huge\tt\color{FF6666}{@Mo}\color{FFB266}{c}\color{B2FF66}{hii}\color{66FF66}{k}\color{66FFFF}{u}\color{66B2FF}{u}\color{6666FF}{}\color{B266FF}{}\color{FF66FF}{}\color{FF66B2}{} \color{FF9999}{}\color{FFCC99}[/tex]

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