Jawaban:

Persamaan Garis Lurus

Penjelasan dengan langkah-langkah:

23. y=-1/3x+3 P(2,3)

tegak lurus

m₁xm₂=-1

-1/3xm₂=-1

m₂=-1/(-1/3)

=-1x(3/-1)

=-1x-3

=3

y-y₁=m(x-x₁)

y-3=3(x-2)

y-3=3x-6

y=3x-6+3

y=3x-3

y-3x+3=0

⇒ Opsi C

24.⇒Opsi A. m₁=-a/b m₂=-a/b

=-2/4 =-4/-2

=-1/2 =2

m₁xm₂=-1

-1/2x2=-1 (√)

B. m₁=-6/-3 m₂=-4/-2

=2 =2

m₁=m₂ (x)

C. m₁=-6/4=-3/2

m₂=-2/-6=1/3

D. m₁=-2/4=-1/2

m₂=-4/2=-2

25. R(3,2) S(5,6) sejajar K(4,6)

m= y₂-y₁

x₂-x₁

= 6-2

5-3

= 4

2

= 2

y-y₁=m(x-x₁)

y-2=2(x-3)

y-2=2x-6

y=2x-6+2

y=2x-4

-2x+y+4=0

m=-a/b

=-(-2)/1

=2

sejajar

m₁=m₂

y-y₁=m(x-x₁)

y-6=2(x-4)

y-6=2x-8

y=2x-8+6

y=2x-2

-2x+y+2=0

⇒Opsi C

Demikian

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