Jawaban:

eliminasi (1) dan (2)

2x + y - z = -1

x + 2y + z = 4

___________+

3x - 3y = -3

_________:3

x - y = -1... (4)

eliminasi (2) dan (3)

x + 2y + z = 4

3x - y + z = -4

___________-

-2x + 3y = 8...(5)

eliminasi (4) dan (5)

x - y = -1 |x2| 2x - 2y = -2

-2x + 3y = 8 |x1| -2x + 3y = 8

_______________________+

y = 6

substitusi nilai y ke (4)

x - y = -1

x - 6 = -1

x = -1 + 6 = 5

substitusi nilai x dan y ke (1)

2x + y - z = -1

2(5) + 6 - z = -1

10 + 6 - z = -1

16 - z = -1

-z = -1-16

-z = -17

_______x-1

z = 17

HP {5, 6, 17}

maka, nilai x+y+z = 5+6+17 = 28

Penjelasan dengan langkah-langkah:

semoga bermanfaat