x² + 2x - 3 = ( x + 3 ) ( x - 1 )

x - k₁ x - k₂

dibagi x - 1 sisa 3

x - 1 = 0

x = 1

f(k₂) = m(k₂) + n

f(1) = m(1) + n

3 = m + n.......(1)

dibagi x + 3 sisa -1

x + 3 = 0

x = -3

f(k₁) = m(k₁) + n

f(-3) = m(-3) + n

-1 = -3m + n.......(2)

Eliminasi 1 & 2 Mencari n

m + n = 3 m + n = 3

-3m + n = -1 1 + n = 3

------------------------ - n = 3 - 1

4m = 4 n = 2

m = 1

f(x) = mx + n

= x + 2

dibagi x - 1 sisa 5

g(k₂) = m(k₂) + n

g(1) = m(1) + n

5 = m + n.....(3)

dibagi x + 3 sisa 1

g(k₁) = m(k₁) + n

g(-3) = m(-3) + n

1 = -3m + n.......(4)

Eliminasi 3 & 4 Mencari n

m + n = 5 m + n = 5

-3m + n = 1 1 + n = 5

-------------------- - n = 5 - 1

4m = 4 n = 4

m = 1

g(x) = mx + n

= x + 4

h(x) = f(x). g(x)

= ( x + 2 )( x + 4 )

= x² + 6x + 8

x² + 6x + 8 = ( x² + 2x - 3 ). k(x) + s(x)

= ( x² + 2x - 3 ).1 + ( 4x + 11 )

x² + 6x + 8 dibagi x² + 2x - 3 hasilnya 1 sisa 4x + 11