1. (x²-5x+6)/(x²+2x-8) =

(x-2)(x-3)/((x-2)(x+4)) =

(x-3)/(x+4)

lim x->2 (x-3)/(x+4) =

(2-3)/(2+4) =

-1/6

2. (x²+5x+6)/(x²+x-2)=

(x+3)(x+2)/((x-1)(x+2)) =

(x+3)/(x-1)

lim x->1 (x+3)/(x-1) =

(1+3)/(1-1) =

4/0 =

∞

3. lim x->2 (3x²-14x+8 )/(x²-3x-4) =

(3(2)²-14×2+8)/(2²-3(2)-4) =

(12-28+8)/(4-6-4) =

-8/-6 =

4/3 =

1⅓

4.(x-4)/(√x -2) =

(√x -2)(√x +2) /(√x -2) =

√x +2

lim x->4 √x +2 =

√4 +2 =

2+2 =

4

5. (9-x²)/(4 - √(x²+7)) =

(9-x²)(4+√(x²+7))/((4-√(x²+7)(4+√(x²+7)) =

(9-x²)(4+√(x²+7))/(16-(x²+7)) =

(9-x²)(4+√(x²+7))/(9-x²) =

4+√(x²+7)

lim x->3 4+√(x²+7) =

4 +√(3²+7) =

4 + 4 =

8

6.lim x->5 (x²-25)/√(x²+2⁴) =

(5²-25)/√(5²+2⁴) =

0/√41 =

0

soal limit lainnya:

yomemimo.com/tugas/10697264

yomemimo.com/tugas/22908184

========================

Detail jawaban:

mapel : matematika

kelas : 11

materi : limit fungsi aljabar

kode soal :2

kode : 11.2 8