Jawab:
½ (E)

Penjelasan dengan langkah-langkah:

g(x) = 1 - 3x
g²(x) - g(x²) + 1 = 0

kiri g(x)-nya dikuadrat
lalu kanan = x² masukin

(1 - 3x)² - (1-3(x²)) + 1 = 0
(1-3x)(1-3x) - (1-3x²) + 1 = 0
1-6x+9x²-1+3x²+1 = 0
12x²-6x+1 = 0
a = 12, b = -6, c = 1

Pake rumus abc
x = -b±√(b²-4ac)/2a
x = -(-6)±√((-6)²-4(12)(1))/2(12)
x = 6±√(36-48)/24
x = 6±√(-12)/24
x = 6±√4√-3/24
x = (6±2√-3)/24
x = (6±2(√3i))/24

maka
x = ¼ ± ¹/₁₂(√3i)

maka
x₁ = ¼ + ¹/₁₂(√3i)
x₂ = ¼ - ¹/₁₂(√3i)

jumlah akar =
x₁ + x₂ =
¼ + ¹/₁₂(√3i) + ¼ - (¹/₁₂(√3i)) =
¼ + ¼ =
½ (E)

<(7o7)>