Jawab:

1

x + y + ½(x)

ᵃlog((∛x)z÷(y⁵))

(1/ab) - (2/b)

Penjelasan dengan langkah-langkah:

(1.) ³log18 - ³log6 = ³log(18:6) = ³log3 =

1

(2.) ²log3 = x, ²log5 = y

²log√675 = ²log15√3 = ²log(5(3)) + ²log√3 = ²log5 + ²log3 + (²log3)/2 =

x + y + ½(x)

(3.) (ᵃlog(x))/3 - 5(ᵃlog(y)) + ᵃlog(z) =

ᵃlog(∛x) - ᵃlog(y⁵) + ᵃlog(z) =

ᵃlog(∛x) + ᵃlog(z) - ᵃlog(y⁵) =

ᵃlog((∛x)z÷(y⁵))

(4.) ⁶log(5) = a, ⁵log(4) = b, maka

⁶log(4) = ab

⁴log(0,24) = ⁴log(6:25) = ⁴log6 - ⁴log25 =

1/(⁶log(4)) - ⁴log(5·5) = 1/(⁶log(4)) - (⁴log(5)+⁴log(5)) =

1/(⁶log(4)) - (1/⁵log(4)+1/⁵log(4)) = 1/ab - (1/b + 1/b) =

(1/ab) - (2/b)

<(7o7)>