Jawab:
9

Penjelasan dengan langkah-langkah:

Kanan dulu yang diselesaiin
log₂5 = log5 ÷ log2
log₃√5 = log√5 ÷ log3
log₂(81) = log₂(3⁴) = 4log₂3 = 4(log3÷log2)

Maka
(log5 ÷ log2) ÷ ((log√5 ÷ log3) × (4(log3÷log2))) =
(log5 ÷ log2) ÷ ((log√5) × (4÷log2)) =
(log5 ÷ log2) ÷ (4log√5 ÷ log2) =
(log5 ÷ log2) × (log2 ÷ 4log√5) =
(log5 ÷ 4log√5) =
(log5 ÷ 4log[5^(1/2)]) =
(log5 ÷ (4/2)log5) =
(log5 ÷ 2log5) =
1/2

Lalu
log_{p²+4} (p+1) = 1/2
log(p+1)/log(p²+4) = 1/2
log(p²+4) = 2log(p+1)
p²+4 = (p+1)²
p²+4 = p²+2p+1
p²-p² +4-1 = 2p
2p = 4-1
2p = 3
p = 3/2

Tentukan nilai 4p²
4(3/2)² = 4(9/4) =
9

[[ KLF ]]