Jawab:

(a.) domain  x ≤ ½

range  f(x) ≥ 0

................................

(b.) domain  x < 1/6, x > 1/6

range  f(x) < 0, f(x) > 0

Penjelasan dengan langkah-langkah:

Domain = batas horizontal

Range = batas vertikal.

................................

(a.) maka domain

1-2x ≥ 0

1 ≥ 2x

2x ≤ 1

x ≤ ½

maka range

√(1-2x) ≥ 0

f(x) ≥ 0

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(b.) maka domain

3-18x ≠ 0

3 ≠ 18x

18x ≠ 3

x ≠ 3/18

x ≠ 1/6 (karena x = 1/6 asimtot tegak)

x < 1/6, x > 1/6

maka range

limₓ→∞(2/(3-18x)) =

2limₓ→∞(1/(3-18x)) =

2(limₓ→∞(1)/(limₓ→∞(3-18x))) =

2(1/-∞) = 0

(y = 0 asimtot datar)

f(x) ≠ 0

f(x) < 0, f(x) > 0

...............................

Sama-sama ya!

<(7o7)>