Jawaban:

1.Jika diketahui fungsi f(x) = -2x + 3 dan g(x) = x² + 6, maka

a.(fog)(1) = -11 dan (gof)(1) = 7.

b.(fog)(0) = -9 dan (gof)(0) = 15

c.(fog)(-2) = -17 dan (gof)(-2) = 55.

2.f(x) = 4x + 5 g(x)= (2x-3)/(4x+7)

gof(x)= g {f(x)} = [ 2(4x+5) - 3 ] /[ 4(4x+5) + 7]

gof(x) = [ 8x+10-3 ] / [ 16x+20+7] gof(x)= (8x +7)/ (16x + 27)

(gof)-¹ {(8x+7)/(16x+27) = x (gof)-¹ (1) = ...

(8x + 7)/(16x + 27) = 1

1(16x + 27) = 8x + 7 16x +27= 8x + 7

16x -8x = 7-27

8x = -20

x = -20/8

x = -5/4

3.Diketahui f(x) = 3x - 10 dan g(x) = 4x + n. Jika (fog)(x) = (gof)(x) maka nilai n yang memenuhi persamaan itu adalah -15

Penjelasan dengan langkah-langkah:

maaf klo salah