Penjelasan dengan langkah-langkah:

2). f(x) = 1 - 4x

misalkan f(x) = y

1 - 4x = y

-4x = y - 1

-(4x) = -(1 - y)

4x = 1 - y

x = (1-y)/4

jadi, fungsi inversnya f^-1(x) = (1-x)/4

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3). f(x) = 2x³ -1

f(x) = y

2x³ - 1 = y

2x³ = y+1

x³ = (y+1)/2

x = ³√(y+1)/2

fungsi invesnya f^-1(x) = ½ . ³√(x+1)

4). 3x² -2x -5 = 0

(3x-5)(x + 1) = 0

solusi:

x1 = 5/3 atau x2 = -1

HP = { -1 , 5/3 }

5). 2x² - 8 = 0

2x² = 8

x = ± √(8/2)

x = ± √4

x = ± 2

6). x² - 2x - 48 = 0

(x - 8)(x + 6) = 0

solusi :

x1 = 8 atau x2 = -6

HP = { -6 , 8 }

7). x² + 4x - 21 = 0

(x + 7)(x - 3) = 0

solusi:

x1 = -7 atau x2 = 3

HP = { -7 , 3 }

8). x² - 5x - 24 = 0

(x - 8)(x + 3) = 0

solusi :

x1 = 8 atau x2 = -3

HP = { -3 , 8 }

9). fungsi Invers

f(x) = 2 - x / (2x + 1)

f(x) = y

y = (2 - x)/(2x + 1)

y(2x +1) = 2 - x

2xy + y = 2 - x

2xy + x = 2 - y

x(2y + 1) = (2 - y)

x = (2 - y)/(2y + 1)

Fungsi inversnya f^-1(x) = (2 - x)/(2x + 1)