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1 . 1per2 tambah 1per3 tambah 1per4=2 . 2per3 tambah

Berikut ini adalah pertanyaan dari yukurilaia5 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

1 . 1per2 tambah 1per3 tambah 1per4=2 . 2per3 tambah 3per7 tambah 1per5=

3 . 6per8 tambah 4per5 tambah 1per5=

4 . 3per6 tambah 2per7 tambah 10per10=

5 . 2per11 tambah 1per5 tambah 1per7=
​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Jawaban:

1.

\frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{6 + 4 + 3}{12} = \frac{13}{12}

2.

\\ \frac{2}{3} + \frac{3}{7 } + \frac{1}{5} = \frac{3}{7} + ( \frac{10 + 3}{15} ) \\ \\ \: \: \: \: \: \: \: = \frac{3}{7} + \frac{13}{15} \\ \\ \: \: \: \: \: \: \: \: \: = \frac{45 + 91}{105 } \\ \\ = \frac{136}{105}

3.

\\ \frac{6}{8} + \frac{4}{5} + \frac{1}{5} = \frac{30 + 32 + 8}{40} = \frac{70}{40} \\ \\ \: \: \: = \frac{14}{8} = \frac{7}{4}

4.

\\ \frac{3}{6} + \frac{2}{7} + \frac{10}{10} = \frac{10}{10} + ( \frac{21 + 12}{42} ) \\ \\ = \frac{10}{10} + \frac{33}{42 \\ } \\ \\ = \frac{420 + 330}{420} \\ \\ = \frac{750}{420} = \frac{75}{42}

5.

\\ \frac{2}{11} + \frac{1}{5} + \frac{1}{7} = \frac{2}{11} + ( \frac{7 + 5}{35} ) \\ \\ = \frac{2}{11} + \frac{12}{35} \\ \\ = \frac{70 +132 }{385} \\ \\ = \frac{202}{385}

Jawaban:1.[tex] \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{6 + 4 + 3}{12} = \frac{13}{12} [/tex]2.[tex] \\ \frac{2}{3} + \frac{3}{7 } + \frac{1}{5} = \frac{3}{7} + ( \frac{10 + 3}{15} ) \\ \\ \: \: \: \: \: \: \: = \frac{3}{7} + \frac{13}{15} \\ \\ \: \: \: \: \: \: \: \: \: = \frac{45 + 91}{105 } \\ \\ = \frac{136}{105} [/tex]3.[tex] \\ \frac{6}{8} + \frac{4}{5} + \frac{1}{5} = \frac{30 + 32 + 8}{40} = \frac{70}{40} \\ \\ \: \: \: = \frac{14}{8} = \frac{7}{4} [/tex]4.[tex] \\ \frac{3}{6} + \frac{2}{7} + \frac{10}{10} = \frac{10}{10} + ( \frac{21 + 12}{42} ) \\ \\ = \frac{10}{10} + \frac{33}{42 \\ } \\ \\ = \frac{420 + 330}{420} \\ \\ = \frac{750}{420} = \frac{75}{42} [/tex]5.[tex] \\ \frac{2}{11} + \frac{1}{5} + \frac{1}{7} = \frac{2}{11} + ( \frac{7 + 5}{35} ) \\ \\ = \frac{2}{11} + \frac{12}{35} \\ \\ = \frac{70 +132 }{385} \\ \\ = \frac{202}{385} [/tex]Jawaban:1.[tex] \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{6 + 4 + 3}{12} = \frac{13}{12} [/tex]2.[tex] \\ \frac{2}{3} + \frac{3}{7 } + \frac{1}{5} = \frac{3}{7} + ( \frac{10 + 3}{15} ) \\ \\ \: \: \: \: \: \: \: = \frac{3}{7} + \frac{13}{15} \\ \\ \: \: \: \: \: \: \: \: \: = \frac{45 + 91}{105 } \\ \\ = \frac{136}{105} [/tex]3.[tex] \\ \frac{6}{8} + \frac{4}{5} + \frac{1}{5} = \frac{30 + 32 + 8}{40} = \frac{70}{40} \\ \\ \: \: \: = \frac{14}{8} = \frac{7}{4} [/tex]4.[tex] \\ \frac{3}{6} + \frac{2}{7} + \frac{10}{10} = \frac{10}{10} + ( \frac{21 + 12}{42} ) \\ \\ = \frac{10}{10} + \frac{33}{42 \\ } \\ \\ = \frac{420 + 330}{420} \\ \\ = \frac{750}{420} = \frac{75}{42} [/tex]5.[tex] \\ \frac{2}{11} + \frac{1}{5} + \frac{1}{7} = \frac{2}{11} + ( \frac{7 + 5}{35} ) \\ \\ = \frac{2}{11} + \frac{12}{35} \\ \\ = \frac{70 +132 }{385} \\ \\ = \frac{202}{385} [/tex]Jawaban:1.[tex] \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{6 + 4 + 3}{12} = \frac{13}{12} [/tex]2.[tex] \\ \frac{2}{3} + \frac{3}{7 } + \frac{1}{5} = \frac{3}{7} + ( \frac{10 + 3}{15} ) \\ \\ \: \: \: \: \: \: \: = \frac{3}{7} + \frac{13}{15} \\ \\ \: \: \: \: \: \: \: \: \: = \frac{45 + 91}{105 } \\ \\ = \frac{136}{105} [/tex]3.[tex] \\ \frac{6}{8} + \frac{4}{5} + \frac{1}{5} = \frac{30 + 32 + 8}{40} = \frac{70}{40} \\ \\ \: \: \: = \frac{14}{8} = \frac{7}{4} [/tex]4.[tex] \\ \frac{3}{6} + \frac{2}{7} + \frac{10}{10} = \frac{10}{10} + ( \frac{21 + 12}{42} ) \\ \\ = \frac{10}{10} + \frac{33}{42 \\ } \\ \\ = \frac{420 + 330}{420} \\ \\ = \frac{750}{420} = \frac{75}{42} [/tex]5.[tex] \\ \frac{2}{11} + \frac{1}{5} + \frac{1}{7} = \frac{2}{11} + ( \frac{7 + 5}{35} ) \\ \\ = \frac{2}{11} + \frac{12}{35} \\ \\ = \frac{70 +132 }{385} \\ \\ = \frac{202}{385} [/tex]

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Last Update: Sun, 16 Oct 22
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