Jawab:
(10.) = -10⁰C (a)
(11.) = turun 11 (c)
(12.) = 1.660 m (c)
(13.) = 62 m (b)
(14.) = -4⁰ (a)

Penjelasan dengan langkah-langkah:

(10.) suhu awal = t₀
suhu awal + 8⁰ = -2⁰
t₀ + 8 = -2 maka
t₀ = -2-8 = -(2+8) = -10
t₀ = -10⁰C (a)

(11.) perubahan suhu = Δt
6⁰ + perubahan = -5⁰
6 + Δt = -5
maka Δt = -5-6 = -(5+6) = -11
Δt = -11 = turun 11 (c)

(12.) turun (-), naik (+)
1800 turun 240 naik 100 =
1.800 - 240 + 100 (m) =
1.660 m (c)

(13.) kedalaman penyelam = h₁
kedalaman - letak dr dasar = penyelam
h₀ - Δh = h₁
80 - 18 = h₁
h₁ = 62 m (b)

(14.) Suhu luar = t₁
suhu dalam kamar - perubahan = suhu luar
t₀ - Δt = t₁
15 - 19 = t₁
t₁ = -(19-15)
t₁ = -4⁰ (a)

(xcvi)