Jawab:

Pilih salah satu

Penjelasan dengan langkah-langkah:

Belok saat y'' = 0

y = sin 2x, 0 ≤ x ≤ 2π

y' = 2 cos 2x

y'' = -4 sin 2x = 0

sin 2x = 0

sin 2x = sin 0

2x = 0 + k · 2π dan 2x = π - 0 + k · 2π

x = 0 + k · π dan x = π/2 + k · π, k bilangan bulat

x = 0 + k · π

k = 0 → x = 0 + 0 · π = 0

k = 1 → x = 0 + 1 · π = π

k = 2 → x = 0 + 2 · π = 2π



x = π/2 + k · π

k = 0 → x = π/2 + 0 · π = π/2

k = 1 → x = π/2 + 1 · π = 3π/2

x = 0 → y = sin 2(0) = 0

x = π/2 → y = sin 2(π/2) = 0

x = π → y = sin 2π = 0

x = 3π/2 → y = sin 2(3π/2) = 0

x = 2π → y = sin 2(2π) = 0

Titik belok nya (0, 0), (π/2, 0), (π, 0), (3π/2, 0) dan (2π, 0)