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kumat ( kuis matematika ) • no 1 : f(x) =

Berikut ini adalah pertanyaan dari Reza01Gaming pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Kumat ( kuis matematika )• no 1 :
f(x) = 2x⁸ + x³ - 6
f(2) = ....

• no 2 :
f(x) = 7x + x³ - 5
f(3) = ...

• no 3 :
f(x) = x² + x³ - x
f(4) = ...

• no 4 :
f(x) = 1 + x - x
f(5) = ...

• no 5 :
f(x) = x² + x³ × x
f(5) = ...


nt :
coba tebak , yang jawab dapat ...

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

➩ Nomor 1

\mathfrak{\bf \sf \tt f(x) = 2x⁸ + x³ - 6}

\mathfrak{\bf \sf \tt f(2) = 2(2⁸) + 2³ - 6}

\mathfrak{\bf \sf \tt f(2) = 2(2 × 2 × 2 × 2 × 2 × 2 × 2 × 2) + ( 2 × 2 × 2 ) - 6}

\mathfrak{\bf \sf \tt f(2) = 2(4 × 2 × 2 × 2 × 2 × 2 × 2) + ( 4 × 2 ) - 6}

\mathfrak{\bf \sf \tt f(2) = 2(8 × 2 × 2 × 2 × 2 × 2) + 8 - 6}

\mathfrak{\bf \sf \tt f(2) = 2(16 × 2 × 2 × 2 × 2) + 8 - 6}

\mathfrak{\bf \sf \tt f(2) = 2(32 × 2 × 2 × 2) + 8 - 6}

\mathfrak{\bf \sf \tt f(2) = 2(64 × 2 × 2) + 8 - 6}

\mathfrak{\bf \sf \tt f(2) = 2(128 × 2) + 8 - 6}

\mathfrak{\bf \sf \tt f(2) = 2(256) + 8 - 6}

\mathfrak{\bf \sf \tt f(2) = 512 + 8 - 6}

\mathfrak{\bf \sf \tt f(2) = 520 - 6}

\bold{\underline{\green{\mathfrak{\bf \sf \tt f(2) = 514 }}}}

➩ Nomor 2

\mathfrak{\bf \sf \tt f(x) = 7x + x³ - 5}

\mathfrak{\bf \sf \tt f(3) = 7(3) + 3³ - 5}

\mathfrak{\bf \sf \tt f(3) = 7(3) + (3×3×3) - 5}

\mathfrak{\bf \sf \tt f(3) = 7(3) + (9×3) - 5}

\mathfrak{\bf \sf \tt f(3) = 7(3) + 27 - 5}

\mathfrak{\bf \sf \tt f(3) = 21 + 27 - 5}

\mathfrak{\bf \sf \tt f(3) = 48 - 5}

\bold{\underline{\green{\mathfrak{\bf \sf \tt f(3) = 43}}}}

➩ Nomor 3

\mathfrak{\bf \sf \tt f(x) = x² + x³ - x}

\mathfrak{\bf \sf \tt f(4) = 4² + 4³ - x}

\mathfrak{\bf \sf \tt f(4) = (4 × 4) + (4 × 4 × 4 ) - 4}

\mathfrak{\bf \sf \tt f(4) = 16 + (16 × 4 ) - 4}

\mathfrak{\bf \sf \tt f(4) = 16 + 64 - 4}

\mathfrak{\bf \sf \tt f(4) = 80 - 4}

\bold{\underline{\green{\mathfrak{\bf \sf \tt f(4) = 76 }}}}

➩ Nomor 4

  • Cara pertama

\mathfrak{\bf \sf \tt f(x) = 1 + x - x}

\mathfrak{\bf \sf \tt f(5) = 1 + 5 - 5}

\mathfrak{\bf \sf \tt f(5) = 6 - 5}

\bold{\underline{\green{\mathfrak{\bf \sf \tt f(5) = 1}}}}

  • Cara kedua

\mathfrak{\bf \sf \tt f(x) = 1 + x - x}

\mathfrak{\bf \sf \tt f(5) = 1 + 5 - 5}

\mathfrak{\bf \sf \tt f(5) = 1 + 0}

\bold{\underline{\green{\mathfrak{\bf \sf \tt f(5) = 1}}}}

➩ Nomor 5

\mathfrak{\bf \sf \tt f(x) = x² + x³ × x}

\mathfrak{\bf \sf \tt f(5) = 5² + 5³ × 5}

\mathfrak{\bf \sf \tt f(5) = (5 × 5)+ (5 × 5 × 5) × 5}

\mathfrak{\bf \sf \tt f(5) = 25 + (25 × 5) × 5}

\mathfrak{\bf \sf \tt f(5) = 25 + 125 × 5}

\mathfrak{\bf \sf \tt f(5) = 25 + 625}

\bold{\underline{\green{\mathfrak{\bf \sf \tt f(5) = 650 }}}}

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Last Update: Tue, 20 Sep 22
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