Jawaban:

Persamaan Garis Lurus

Penjelasan dengan langkah-langkah:

1. a. m=(y₂-y₁) P(-1,2) Q(1,1)

(x₂-x₁)

=(1-2)

(1-(-1)

=(-1)

(1+1)

=(-1)

(2)

=-1/2

b. Y-y₁=m(X-x₁)

Y-2=-1/2(X-(-1)

Y-2=-1/2(X+1)

Y-2=-1/2X-1/2

Y=-1/2X-1/2+2

Y=-1/2X-1/2+4/2

Y=-1/2X+3/2

----------------- x 2

2Y=-X+3

X+2Y=3

X+2Y-3=0

2. Garis K (0,-4) dan (3,0)

m=(y₂-y₁)

(x₂-x₁)

=(0-(-4)

(3-0)

=(0+4)

(3)

= 4

3

M₁xM₂=-1

4/3xM₂=-1

M₂=-1/(4/3)

M₂=-1x(3/4)

M₂=-3/4

(2,1)

Y-y₁=m(X-x₁)

Y-1=-3/4(X-2)

Y-1=-3/4X+6/4

Y=-3/4X+6/4+1

Y=-3/4X+6/4+4/4

Y=-3/4X+10/4

------------------- x 4

4Y=-3X+10

3X+4Y=10

3x+4Y-10=0

Detail Jawaban:

Mapel : Matematika

Kelas : 8 / VIII SMP

Materi : Persamaan Garis Lurus

Kode Kategorisasi : -

Kata Kunci : Persamaan Garis Lurus

Demikian

Semoga membantu dan bermanfaat!