Jawab:

Penjelasan dengan langkah-langkah:

1. f(x) = 3x + 4 (x²-2)

a.) f(c) = 3(c) + 4 ((c)²-2)

f(c)= 3c +4 (c² - 2)

f(c)= 3c + 4c² - 8

b.) f(a+b) = 3(a+b) + 4 ((a+b)²-2)

f(a+b)= 3(a)+3(b) +4 ((a+b)(a+b) - 2)

f(a+b)=3a+3b +4 ((a²+2ab+b²)-2)

f(a+b)=3a+3b +4a²+8ab+4b²- 8

f(a+b)=4a²+4b²+8ab+3a+3b-8

c.)f(2)= 3(2)+4((2)²-2)

f(2) = 6+4(4-2)

f(2) =6+16-8

f(2) =14

2.)h(x)= 2(x) - 4x²

a.)h(a+b)= 2(a+b) - 4 (a+b)²

h(a+b)= 2a+2b- 4(a²+2ab+b²)

h(a+b)= 2a+2b- 4a²-8ab - 4b²

h(a+b)= -4a²-4b²-8ab+2a+2b

b.)h(4)=2(4)- 4(4)²

h(4)=8-64

h(4)= -56