tolong kakkkkkkkkklllll​

Berikut ini adalah pertanyaan dari setiopra199 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Tolong kakkkkkkkkklllll​
tolong kakkkkkkkkklllll​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

  • Garis 1:

Titik potong sumbu x = (8, 0)

Titik potong sumbu y = (4, 0)

Menentukan persamaan:

Gunakan cara cepat menentukan persamaan dari titik potong sumbu x dan y:

(Sumbu y)x + (Sumbu x)y = (Sumbu x × Sumbu y)

4x + 8y = (4×8)

4x + 8y = 32

x + y = 8 → dibagi 4

Menentukan tanda:

Gunakan uji titik 0

Di grafik terlihat bahwa 0 termasuk daerah HP, maka buat pernyataan benar

Saat x dan y = 0, maka

0 + 0 = 8

0 ... 8

0 ≤ 8 → pernyataan benar

x + y 8

  • Garis 2:

Titik potong sumbu x = (5, 0)

Titik potong sumbu y = (5, 0)

Menentukan persamaan:

(Sumbu y)x + (Sumbu x)y = (Sumbu x × Sumbu y)

5x + 5y = (5×5)

5x + 5y = 25

x + y = 5 → dibagi 5

Menentukan tanda:

Uji titik 0, 0 termasuk daerah HP maka buat pernyataan benar

Saat x dan y = 0, maka

0 + 0 = 5

0 ... 5

0 ≤ 5 → pernyataan benar

x + y 5

  • Garis 3: y ≥ 0
  • Garis 4: x ≥ 0

Jadi, bentuk persamaan daerah HP pada grafik tersebut adalah:

x + y 8

x + y 5

y 0

x 0

Semoga membantu, jika ada yang perlu ditanyakan tulis di kolom komentar ya

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Garis 1:Titik potong sumbu x = (8, 0)Titik potong sumbu y = (4, 0)Menentukan persamaan:Gunakan cara cepat menentukan persamaan dari titik potong sumbu x dan y:(Sumbu y)x + (Sumbu x)y = (Sumbu x × Sumbu y)4x + 8y = (4×8)4x + 8y = 32x + y = 8 → dibagi 4Menentukan tanda:Gunakan uji titik 0Di grafik terlihat bahwa 0 termasuk daerah HP, maka buat pernyataan benarSaat x dan y = 0, maka0 + 0 = 80 ... 80 ≤ 8 → pernyataan benarx + y ≤ 8Garis 2:Titik potong sumbu x = (5, 0)Titik potong sumbu y = (5, 0)Menentukan persamaan:(Sumbu y)x + (Sumbu x)y = (Sumbu x × Sumbu y)5x + 5y = (5×5)5x + 5y = 25x + y = 5 → dibagi 5Menentukan tanda:Uji titik 0, 0 termasuk daerah HP maka buat pernyataan benarSaat x dan y = 0, maka0 + 0 = 50 ... 50 ≤ 5 → pernyataan benarx + y ≤ 5Garis 3: y ≥ 0Garis 4: x ≥ 0Jadi, bentuk persamaan daerah HP pada grafik tersebut adalah:x + y ≤ 8x + y ≤ 5y ≥ 0x ≥ 0Semoga membantu, jika ada yang perlu ditanyakan tulis di kolom komentar ya[tex]\boxed{\begin{array}{c}\color{FF0000}{\rule{5pt}{5pt}}\color{FF5900}{\rule{5pt}{5pt}}\color{FF8800}{\rule{5pt}{5pt}}\color{FFBF00}{\rule{5pt}{5pt}}\color{FFE100}{\rule{5pt}{5pt}}\color{EDFF00}{\rule{5pt}{5pt}}\color{AEFF00}{\rule{5pt}{5pt}}\color{11FF00}{\rule{5pt}{5pt}}\color{00FF9D}{\rule{5pt}{5pt}}\color{00FFEE}{\rule{5pt}{5pt}}\color{00E5FF}{\rule{5pt}{5pt}}\color{00B2FF}{\rule{5pt}{5pt}}\color{005DFF}{\rule{5pt}{5pt}}\color{0004FF}{\rule{5pt}{5pt}}\color{6E00FF}{\rule{5pt}{5pt}}\color{C300FF}{\rule{5pt}{5pt}}\color{F200FF}{\rule{5pt}{5pt}}\color{FF00B2}{\rule{5pt}{5pt}}\color{FF007F}{\rule{5pt}{5pt}}\\\ \colorbox{black}{\color{white}{\bf @IAblitz}}\\\ \color{FF007F}{\rule{5pt}{5pt}}\color{FF00B2}{\rule{5pt}{5pt}}\color{F200FF}{\rule{5pt}{5pt}}\color{C300FF}{\rule{5pt}{5pt}}\color{6E00FF}{\rule{5pt}{5pt}}\color{0004FF}{\rule{5pt}{5pt}}\color{005DFF}{\rule{5pt}{5pt}}\color{00B2FF}{\rule{5pt}{5pt}}\color{00E5FF}{\rule{5pt}{5pt}}\color{00FFEE}{\rule{5pt}{5pt}}\color{00FF9D}{\rule{5pt}{5pt}}\color{11FF00}{\rule{5pt}{5pt}}\color{AEFF00}{\rule{5pt}{5pt}}\color{EDFF00}{\rule{5pt}{5pt}}\color{FFE100}{\rule{5pt}{5pt}}\color{FFBF00}{\rule{5pt}{5pt}}\color{FF8800}{\rule{5pt}{5pt}}\color{FF5900}{\rule{5pt}{5pt}}\color{FF0000}{\rule{5pt}{5pt}}\end{array}}[/tex]

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Last Update: Sun, 04 Jun 23