Penjelasan dengan langkah-langkah:

32) -x+y+z = -4

x+2y+z = 0

2x+3y+z = 1

x+y+z = ...??

-x+y+z = -4

x+2y+z = 0

----------------- (-) ... eleminasi nilai z

-2x-y = 4 ← diperoleh pers 1

x+2y+z = 0

2x+3y+z = 1

------------------ (-) .... eleminasi nilai z

-x-y = -1 ← diperoleh pers 2

hitung pers 1 dan 2

-2x-y = 4 → kali -1

-x-y = -1 → kali -2

2x+y = -4

2x+2y = 2

----------------- (-) ... eleminasi nilai x

-y = -6

y = 6 ← diperoleh nilai y

-x-y = -1

-x-6 = -1

-x = -1+6

x = -5 ← diperoleh nilai x

-x+y+z = -4

-(-5)+6+z=-4

11 + z = -4

z = -4-11

z = -15 ← diperoleh nilai z

maka

x+y+z

= -5+6-15

= -14

Diketahui :

f = {(-6,4);(3,3);(2,5);(8,1)}

g = {(-4,-6);(2,3);(3,2);(7,8)}

33) f⁰g ..??

f⁰g → f(g(x)

Cara menentukan f⁰g

(domain g) → (kodomain g/domain f) → (kodomain f)

-4 → -6 → 4

2 → 3 → 3

3 → 2 → 5

7 → 8 → 1

maka f⁰g = {(-4,4);(2,3);(3,5);(7,1)}

34) f⁰g(3)

f(g(3) = 5

35) Diketahui :

f(x) = x+1

g(x) = x-5

a) f⁰g(x)

f(g(x) = (x-5)+1

= x-4

maka f⁰g(x) = x-4

b) f⁰g(2) = 2-4

= -2

maka f⁰g(2) = -2