Penjelasan dengan langkah-langkah:

a) f(x) = 2x² + 5

f⁻¹(x) = \sqrt{\frac{x - c}{a} }

a

x−c

f⁻¹(x) = \sqrt{\frac{x - 5}{2} }

2

x−5

b) g(x) = \frac{2x - 1}{6}}

g⁻¹(x) = \frac{cx - b}{a}}

g⁻¹(x) = \frac{6x + 1}{2}}

c) h(x) = \sqrt[3]{x + 2}

3

x+2

h⁻¹(x) = \frac{x^{n} - b}{a}

a

x

n

−b

h⁻¹(x) = x³ - 2

Cara II (Biasa)

a) f(x) = 2x² + 5

f(x) = y

2x² + 5 = y

2x² = y - 5

x² = \frac{y - 5}{2}

2

y−5

x = \sqrt{\frac{y - 5}{2}}

2

y−5

∴ f⁻¹(x) = \sqrt{\frac{x - 5}{2} }

2

x−5

b) g(x) = \frac{2x - 1}{6}}

g(x) = y

\frac{2x - 1}{6}} = y

2x - 1 = 6y

2x = 6y + 1

x = \frac{6y + 1}{2}}

∴ g⁻¹(x) = \frac{6x + 1}{2}}

c) h(x) = \sqrt[3]{x + 2}

3

x+2

h(x) = y

\sqrt[3]{x + 2}

3

x+2

= y

(\sqrt[3]{x + 2}

3

x+2

)³ = y³

x + 2 = y³

x = y³ - 3

∴ h⁻¹(x) = x³ - 2