To solve this problem, we need to find the values ​​of the roots of the quadratic equation first, and then calculate the values ​​of the given expressions. To find the roots of the quadratic equation x² - 3x - 18 = 0, we can use the quadratic formula: x = [-b ± √(b² - 4ac)] / 2a In this quadratic equation, a = 1, b = -3, and c = -18. Substituting these values ​​into the quadratic formula, we get: x = [-(-3) ± √((-3)² - 4(1)(-18))] / 2(1) x = [3 ± √(105)] / 2 So the roots of this quadratic equation are: x1 = (3 + √105) / 2 x2 = (3 - √105) / 2 Now we can calculate the value of the expression (x1 - 2) + (x2 - 2) as follows: (x1 - 2) + (x2 - 2) = x1 + x2 - 4 Substituting the found x1 and x2 values, we get: (x1 - 2) + (x2 - 2) = [(3 + √105) / 2] + [(3 - √105) / 2] - 4 (x1 - 2) + (x2 - 2) = 3 - √105 + 3 + √105 - 4 (x1 - 2) + (x2 - 2) = 2 So the value of the expression (x1 - 2) + (x2 - 2) is 2.