Jawab:
[bentuk sederhana]
c¹² ÷ a⁶ = (a⁴ - 50a² + 616)⁴ ÷ a⁶

Jika c¹² ÷ a⁶ = 0, maka
-->  a = {-2√7, 2√7, -√22, √22}
-->  c = 0

Penjelasan:
a² + b³ = 25
b³ = 25 - a²
(b³)² = (25 - a²)²
b⁶ = (25 - a²)²

b⁶ - c³ = 9
(25 - a²)² - c³ = 9
c³ = (25 - a²)² - 9
(c³)⁴ = ((25 - a²)² - 9)⁴
c¹² = ((25 - a²)² - 9)⁴

c¹² ÷ a⁶ =
((25 - a²)² - 9)⁴ ÷ a⁶ =
(25²-2(25)(a²)+(a²)² - 9)⁴ ÷ a⁶
(625-50a²+a⁴ - 9)⁴ ÷ a⁶
(a⁴ - 50a² + 616)⁴ ÷ a⁶

Jika c¹² ÷ a⁶ = 0, maka nilai a
(a⁴ - 50a² + 616)⁴ ÷ a⁶ = 0
a⁴ - 50a² + 616 = 0
(a²)² - 50(a²) + 616 = 0
--> u = a²
u² - 50u + 616 = 0
u = [-(-50)±√((-50)²-4(1)(616))]/(2(1))
u = [50±√(2500-2464)]/2
u = [50±√36]/2
u = [50±6]/2
u = (50/2) ± (6/2)
u = 25 ± 3
u = 25 + 3    u = 25 - 3
u = 28,         u = 22
a² = 28,        a² = 22
|a| = √28,     |a| = √22
|a| = √4√7,   |a| = √22
|a| = 2√7,      |a| = √22
a = {-2√7, 2√7, -√22, √22}

Jika c¹² ÷ a⁶ = 0, maka nilai c = 0

(xcvi)