Niai dari 6√3 + √27 + 2√48 adalah...

Berikut ini adalah pertanyaan dari setyoko1683 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Niai dari 6√3 + √27 + 2√48 adalah...

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

\large{ \colorbox{lavender}{ \purple{ \boxed{ \green{ \star{ \purple{ \rm{«Penyelesaian \: Soal»: \green{ \star}}}}}}}}}

 \:

\huge{ \purple{ \mathfrak{♡Pembahasan♡ : }}}

 \:

 \begin{gathered} \boxed{ \boxed{ \begin{aligned} \underline{ \blue{ \sf{6 \sqrt{3} + \sqrt{27} + 2\sqrt{48} }}} \\ \sf{ = 6 \sqrt{3} + \sqrt{9 \times 3} + 2 \times \sqrt{16 \times 3} } \\ \sf{ = 6 \sqrt{3} + \sqrt{ {3}^{2} \times 3 } + 2 \times \sqrt{ {4}^{2} \times 3 } } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 2 \times 4 \sqrt{3} } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (6 + 3) \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = 9 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (9 + 8) \sqrt{3} } \\ \sf{ = \underline{ \red{17 \sqrt{3} }}}\end{aligned}}} \end{gathered}

 \:

_________________________________________________________________________________________________________________________

 \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\

=======

\colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{}

 \:

\colorbox{black} { \blue{ \boxed{ \boxed{\rm\color{FF6666}{༆@}\color{FFB266}{O}\color{B2FF66}{n}\color{66FF66}{l}\color{66FFFF}{y}\color{66B2FF}{Y}\color{6666FF}{o}\color{B266FF}{o}\color{FF66FF}{j}\color{FF66B2}{i}\color{FF9999}{n}\color{FFCC99}{࿐}}}}}

[tex]\large{ \colorbox{lavender}{ \purple{ \boxed{ \green{ \star{ \purple{ \rm{«Penyelesaian \: Soal»: \green{ \star}}}}}}}}}[/tex][tex] \: [/tex][tex]\huge{ \purple{ \mathfrak{♡Pembahasan♡ : }}}[/tex][tex] \: [/tex][tex] \begin{gathered} \boxed{ \boxed{ \begin{aligned} \underline{ \blue{ \sf{6 \sqrt{3} + \sqrt{27} + 2\sqrt{48} }}} \\ \sf{ = 6 \sqrt{3} + \sqrt{9 \times 3} + 2 \times \sqrt{16 \times 3} } \\ \sf{ = 6 \sqrt{3} + \sqrt{ {3}^{2} \times 3 } + 2 \times \sqrt{ {4}^{2} \times 3 } } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 2 \times 4 \sqrt{3} } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (6 + 3) \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = 9 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (9 + 8) \sqrt{3} } \\ \sf{ = \underline{ \red{17 \sqrt{3} }}}\end{aligned}}} \end{gathered}[/tex][tex] \: [/tex][tex]_________________________________________________________________________________________________________________________[/tex][tex] \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ [/tex]=======[tex]\colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{}[/tex][tex] \: [/tex][tex]\colorbox{black} { \blue{ \boxed{ \boxed{\rm\color{FF6666}{༆@}\color{FFB266}{O}\color{B2FF66}{n}\color{66FF66}{l}\color{66FFFF}{y}\color{66B2FF}{Y}\color{6666FF}{o}\color{B266FF}{o}\color{FF66FF}{j}\color{FF66B2}{i}\color{FF9999}{n}\color{FFCC99}{࿐}}}}}[/tex][tex]\large{ \colorbox{lavender}{ \purple{ \boxed{ \green{ \star{ \purple{ \rm{«Penyelesaian \: Soal»: \green{ \star}}}}}}}}}[/tex][tex] \: [/tex][tex]\huge{ \purple{ \mathfrak{♡Pembahasan♡ : }}}[/tex][tex] \: [/tex][tex] \begin{gathered} \boxed{ \boxed{ \begin{aligned} \underline{ \blue{ \sf{6 \sqrt{3} + \sqrt{27} + 2\sqrt{48} }}} \\ \sf{ = 6 \sqrt{3} + \sqrt{9 \times 3} + 2 \times \sqrt{16 \times 3} } \\ \sf{ = 6 \sqrt{3} + \sqrt{ {3}^{2} \times 3 } + 2 \times \sqrt{ {4}^{2} \times 3 } } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 2 \times 4 \sqrt{3} } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (6 + 3) \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = 9 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (9 + 8) \sqrt{3} } \\ \sf{ = \underline{ \red{17 \sqrt{3} }}}\end{aligned}}} \end{gathered}[/tex][tex] \: [/tex][tex]_________________________________________________________________________________________________________________________[/tex][tex] \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ [/tex]=======[tex]\colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{}[/tex][tex] \: [/tex][tex]\colorbox{black} { \blue{ \boxed{ \boxed{\rm\color{FF6666}{༆@}\color{FFB266}{O}\color{B2FF66}{n}\color{66FF66}{l}\color{66FFFF}{y}\color{66B2FF}{Y}\color{6666FF}{o}\color{B266FF}{o}\color{FF66FF}{j}\color{FF66B2}{i}\color{FF9999}{n}\color{FFCC99}{࿐}}}}}[/tex][tex]\large{ \colorbox{lavender}{ \purple{ \boxed{ \green{ \star{ \purple{ \rm{«Penyelesaian \: Soal»: \green{ \star}}}}}}}}}[/tex][tex] \: [/tex][tex]\huge{ \purple{ \mathfrak{♡Pembahasan♡ : }}}[/tex][tex] \: [/tex][tex] \begin{gathered} \boxed{ \boxed{ \begin{aligned} \underline{ \blue{ \sf{6 \sqrt{3} + \sqrt{27} + 2\sqrt{48} }}} \\ \sf{ = 6 \sqrt{3} + \sqrt{9 \times 3} + 2 \times \sqrt{16 \times 3} } \\ \sf{ = 6 \sqrt{3} + \sqrt{ {3}^{2} \times 3 } + 2 \times \sqrt{ {4}^{2} \times 3 } } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 2 \times 4 \sqrt{3} } \\ \sf{ = 6 \sqrt{3} + 3 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (6 + 3) \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = 9 \sqrt{3} + 8 \sqrt{3} } \\ \sf{ = (9 + 8) \sqrt{3} } \\ \sf{ = \underline{ \red{17 \sqrt{3} }}}\end{aligned}}} \end{gathered}[/tex][tex] \: [/tex][tex]_________________________________________________________________________________________________________________________[/tex][tex] \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ [/tex]=======[tex]\colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{}[/tex][tex] \: [/tex][tex]\colorbox{black} { \blue{ \boxed{ \boxed{\rm\color{FF6666}{༆@}\color{FFB266}{O}\color{B2FF66}{n}\color{66FF66}{l}\color{66FFFF}{y}\color{66B2FF}{Y}\color{6666FF}{o}\color{B266FF}{o}\color{FF66FF}{j}\color{FF66B2}{i}\color{FF9999}{n}\color{FFCC99}{࿐}}}}}[/tex]

Semoga dengan pertanyaan yang sudah terjawab oleh OnlyYoojin dapat membantu memudahkan mengerjakan soal, tugas dan PR sekolah kalian.

Apabila terdapat kesalahan dalam mengerjakan soal, silahkan koreksi jawaban dengan mengirimkan email ke yomemimo.com melalui halaman Contact

Last Update: Wed, 30 Nov 22