Jawab:

Penjelasan dengan langkah-langkah:

S = {1, 2, 3, 4, 5, 6}

n(S) = 6

A = kejadian muncul mata dadu prima

A = {2, 3, 5}

n(A) = 3

P(A) = 3/6 = ½

B = kejadian muncul mata dadu ganjil

B = {1, 3, 5}

n(B) = 3

P(B) = 3/6 = ½

C = kejadian muncul mata dadu kurang dari 5

C = {1, 2, 3, 4}

n(C) = 4

P(C) = 4/6 = ⅔

Banyak lambungan = 310 kali.

Fh(A) = P(A) x 310

Fh(A) = ½ x 310

Fh(A) = 155

Fh(B) = P(B) x 310

Fh(B) = ½ x 310

Fh(B) = 155

Fh(C) = P(C) x 310

Fh(C) = ⅔ x 310

Fh(C) = 206.67