Berikut ini adalah pertanyaan dari dertrayblood pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas
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Jawaban dan Penjelasan
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Jawaban:
mohon maaf jika sya slah ya .... mohon jg di koksi dan bantu fllow ig [email protected] makasih
![Penjelasan dengan langkah-langkah:[tex] a).\sqrt{27} + \sqrt{12} - \sqrt{300} \\ = \sqrt{9.3} + \sqrt{4.3} - \sqrt{100.3} \\ = 3 \sqrt{3} + 2 \sqrt{3} - 10 \sqrt{3} \\ = 3 + 2 - 10 \sqrt{3} \\ = 5 - 10 \sqrt{3} \\ = - 5 \sqrt{3} [/tex][tex]b). \sqrt{8} - \sqrt{20} + \sqrt{50} - \sqrt{80} \\ = \sqrt{4.2} - \sqrt{4.5} + \sqrt{25 \times 2} - \sqrt{16.5} \\ = 2 \sqrt{2} - 2 \sqrt{5} + 5 \sqrt{2} - 4 \sqrt{5} \\ = (2 \sqrt{2} + 5 \sqrt{2} ) ( - 2 \sqrt{5} - 4 \sqrt{5} ) \\ = 7 \sqrt{2} - 6 \sqrt{5} [/tex][tex]c). \sqrt{75} - \sqrt{48} + \sqrt{28} \\ = \sqrt{25.3} - \sqrt{16.3} + \sqrt{4.7} \\ = 5 \sqrt{3} - 4 \sqrt{3} + 2\sqrt{7} \\ = 1 \sqrt{3} + 2 \sqrt{7} \\ = \sqrt{3} + 2 \sqrt{7} [/tex][tex]d). \sqrt{24} - \sqrt{150} - \sqrt{54} + \sqrt{600} \\ = \sqrt{4.6} - \sqrt{25.6} - \sqrt{9.6} + \sqrt{100.6} \\ = 2 \sqrt{6} - 5 \sqrt{6} - 3 \sqrt{6} + 10 \sqrt{6} \\ = (2 - 5 - 3 + 10) \sqrt{6} \\ = 4 \sqrt{6} [/tex][tex]e). \sqrt{9} + \sqrt{200} - \sqrt{72} \\ = 3 + \sqrt{100.2} - \sqrt{36.2} \\ = 3 + 10 \sqrt{2} - 6 \sqrt{2} \\ = 3 + 4 \sqrt{2} [/tex]](https://id-static.z-dn.net/files/da3/53da1199afd6a35d51f9787fa6c4e53d.jpg)
![Penjelasan dengan langkah-langkah:[tex] a).\sqrt{27} + \sqrt{12} - \sqrt{300} \\ = \sqrt{9.3} + \sqrt{4.3} - \sqrt{100.3} \\ = 3 \sqrt{3} + 2 \sqrt{3} - 10 \sqrt{3} \\ = 3 + 2 - 10 \sqrt{3} \\ = 5 - 10 \sqrt{3} \\ = - 5 \sqrt{3} [/tex][tex]b). \sqrt{8} - \sqrt{20} + \sqrt{50} - \sqrt{80} \\ = \sqrt{4.2} - \sqrt{4.5} + \sqrt{25 \times 2} - \sqrt{16.5} \\ = 2 \sqrt{2} - 2 \sqrt{5} + 5 \sqrt{2} - 4 \sqrt{5} \\ = (2 \sqrt{2} + 5 \sqrt{2} ) ( - 2 \sqrt{5} - 4 \sqrt{5} ) \\ = 7 \sqrt{2} - 6 \sqrt{5} [/tex][tex]c). \sqrt{75} - \sqrt{48} + \sqrt{28} \\ = \sqrt{25.3} - \sqrt{16.3} + \sqrt{4.7} \\ = 5 \sqrt{3} - 4 \sqrt{3} + 2\sqrt{7} \\ = 1 \sqrt{3} + 2 \sqrt{7} \\ = \sqrt{3} + 2 \sqrt{7} [/tex][tex]d). \sqrt{24} - \sqrt{150} - \sqrt{54} + \sqrt{600} \\ = \sqrt{4.6} - \sqrt{25.6} - \sqrt{9.6} + \sqrt{100.6} \\ = 2 \sqrt{6} - 5 \sqrt{6} - 3 \sqrt{6} + 10 \sqrt{6} \\ = (2 - 5 - 3 + 10) \sqrt{6} \\ = 4 \sqrt{6} [/tex][tex]e). \sqrt{9} + \sqrt{200} - \sqrt{72} \\ = 3 + \sqrt{100.2} - \sqrt{36.2} \\ = 3 + 10 \sqrt{2} - 6 \sqrt{2} \\ = 3 + 4 \sqrt{2} [/tex]](https://id-static.z-dn.net/files/d52/2ae5a723d47f02f88edd91b60f37a2b9.jpg)
![Penjelasan dengan langkah-langkah:[tex] a).\sqrt{27} + \sqrt{12} - \sqrt{300} \\ = \sqrt{9.3} + \sqrt{4.3} - \sqrt{100.3} \\ = 3 \sqrt{3} + 2 \sqrt{3} - 10 \sqrt{3} \\ = 3 + 2 - 10 \sqrt{3} \\ = 5 - 10 \sqrt{3} \\ = - 5 \sqrt{3} [/tex][tex]b). \sqrt{8} - \sqrt{20} + \sqrt{50} - \sqrt{80} \\ = \sqrt{4.2} - \sqrt{4.5} + \sqrt{25 \times 2} - \sqrt{16.5} \\ = 2 \sqrt{2} - 2 \sqrt{5} + 5 \sqrt{2} - 4 \sqrt{5} \\ = (2 \sqrt{2} + 5 \sqrt{2} ) ( - 2 \sqrt{5} - 4 \sqrt{5} ) \\ = 7 \sqrt{2} - 6 \sqrt{5} [/tex][tex]c). \sqrt{75} - \sqrt{48} + \sqrt{28} \\ = \sqrt{25.3} - \sqrt{16.3} + \sqrt{4.7} \\ = 5 \sqrt{3} - 4 \sqrt{3} + 2\sqrt{7} \\ = 1 \sqrt{3} + 2 \sqrt{7} \\ = \sqrt{3} + 2 \sqrt{7} [/tex][tex]d). \sqrt{24} - \sqrt{150} - \sqrt{54} + \sqrt{600} \\ = \sqrt{4.6} - \sqrt{25.6} - \sqrt{9.6} + \sqrt{100.6} \\ = 2 \sqrt{6} - 5 \sqrt{6} - 3 \sqrt{6} + 10 \sqrt{6} \\ = (2 - 5 - 3 + 10) \sqrt{6} \\ = 4 \sqrt{6} [/tex][tex]e). \sqrt{9} + \sqrt{200} - \sqrt{72} \\ = 3 + \sqrt{100.2} - \sqrt{36.2} \\ = 3 + 10 \sqrt{2} - 6 \sqrt{2} \\ = 3 + 4 \sqrt{2} [/tex]](https://id-static.z-dn.net/files/def/72de8e20793b4f6c0bd514ac1a664c99.jpg)
![Penjelasan dengan langkah-langkah:[tex] a).\sqrt{27} + \sqrt{12} - \sqrt{300} \\ = \sqrt{9.3} + \sqrt{4.3} - \sqrt{100.3} \\ = 3 \sqrt{3} + 2 \sqrt{3} - 10 \sqrt{3} \\ = 3 + 2 - 10 \sqrt{3} \\ = 5 - 10 \sqrt{3} \\ = - 5 \sqrt{3} [/tex][tex]b). \sqrt{8} - \sqrt{20} + \sqrt{50} - \sqrt{80} \\ = \sqrt{4.2} - \sqrt{4.5} + \sqrt{25 \times 2} - \sqrt{16.5} \\ = 2 \sqrt{2} - 2 \sqrt{5} + 5 \sqrt{2} - 4 \sqrt{5} \\ = (2 \sqrt{2} + 5 \sqrt{2} ) ( - 2 \sqrt{5} - 4 \sqrt{5} ) \\ = 7 \sqrt{2} - 6 \sqrt{5} [/tex][tex]c). \sqrt{75} - \sqrt{48} + \sqrt{28} \\ = \sqrt{25.3} - \sqrt{16.3} + \sqrt{4.7} \\ = 5 \sqrt{3} - 4 \sqrt{3} + 2\sqrt{7} \\ = 1 \sqrt{3} + 2 \sqrt{7} \\ = \sqrt{3} + 2 \sqrt{7} [/tex][tex]d). \sqrt{24} - \sqrt{150} - \sqrt{54} + \sqrt{600} \\ = \sqrt{4.6} - \sqrt{25.6} - \sqrt{9.6} + \sqrt{100.6} \\ = 2 \sqrt{6} - 5 \sqrt{6} - 3 \sqrt{6} + 10 \sqrt{6} \\ = (2 - 5 - 3 + 10) \sqrt{6} \\ = 4 \sqrt{6} [/tex][tex]e). \sqrt{9} + \sqrt{200} - \sqrt{72} \\ = 3 + \sqrt{100.2} - \sqrt{36.2} \\ = 3 + 10 \sqrt{2} - 6 \sqrt{2} \\ = 3 + 4 \sqrt{2} [/tex]](https://id-static.z-dn.net/files/d88/7e88047f635eb8af32730f0299b8fc8c.jpg)
![Penjelasan dengan langkah-langkah:[tex] a).\sqrt{27} + \sqrt{12} - \sqrt{300} \\ = \sqrt{9.3} + \sqrt{4.3} - \sqrt{100.3} \\ = 3 \sqrt{3} + 2 \sqrt{3} - 10 \sqrt{3} \\ = 3 + 2 - 10 \sqrt{3} \\ = 5 - 10 \sqrt{3} \\ = - 5 \sqrt{3} [/tex][tex]b). \sqrt{8} - \sqrt{20} + \sqrt{50} - \sqrt{80} \\ = \sqrt{4.2} - \sqrt{4.5} + \sqrt{25 \times 2} - \sqrt{16.5} \\ = 2 \sqrt{2} - 2 \sqrt{5} + 5 \sqrt{2} - 4 \sqrt{5} \\ = (2 \sqrt{2} + 5 \sqrt{2} ) ( - 2 \sqrt{5} - 4 \sqrt{5} ) \\ = 7 \sqrt{2} - 6 \sqrt{5} [/tex][tex]c). \sqrt{75} - \sqrt{48} + \sqrt{28} \\ = \sqrt{25.3} - \sqrt{16.3} + \sqrt{4.7} \\ = 5 \sqrt{3} - 4 \sqrt{3} + 2\sqrt{7} \\ = 1 \sqrt{3} + 2 \sqrt{7} \\ = \sqrt{3} + 2 \sqrt{7} [/tex][tex]d). \sqrt{24} - \sqrt{150} - \sqrt{54} + \sqrt{600} \\ = \sqrt{4.6} - \sqrt{25.6} - \sqrt{9.6} + \sqrt{100.6} \\ = 2 \sqrt{6} - 5 \sqrt{6} - 3 \sqrt{6} + 10 \sqrt{6} \\ = (2 - 5 - 3 + 10) \sqrt{6} \\ = 4 \sqrt{6} [/tex][tex]e). \sqrt{9} + \sqrt{200} - \sqrt{72} \\ = 3 + \sqrt{100.2} - \sqrt{36.2} \\ = 3 + 10 \sqrt{2} - 6 \sqrt{2} \\ = 3 + 4 \sqrt{2} [/tex]](https://id-static.z-dn.net/files/d42/5784b61b8d4712dd4b8aa26ea0865e38.jpg)
![Penjelasan dengan langkah-langkah:[tex] a).\sqrt{27} + \sqrt{12} - \sqrt{300} \\ = \sqrt{9.3} + \sqrt{4.3} - \sqrt{100.3} \\ = 3 \sqrt{3} + 2 \sqrt{3} - 10 \sqrt{3} \\ = 3 + 2 - 10 \sqrt{3} \\ = 5 - 10 \sqrt{3} \\ = - 5 \sqrt{3} [/tex][tex]b). \sqrt{8} - \sqrt{20} + \sqrt{50} - \sqrt{80} \\ = \sqrt{4.2} - \sqrt{4.5} + \sqrt{25 \times 2} - \sqrt{16.5} \\ = 2 \sqrt{2} - 2 \sqrt{5} + 5 \sqrt{2} - 4 \sqrt{5} \\ = (2 \sqrt{2} + 5 \sqrt{2} ) ( - 2 \sqrt{5} - 4 \sqrt{5} ) \\ = 7 \sqrt{2} - 6 \sqrt{5} [/tex][tex]c). \sqrt{75} - \sqrt{48} + \sqrt{28} \\ = \sqrt{25.3} - \sqrt{16.3} + \sqrt{4.7} \\ = 5 \sqrt{3} - 4 \sqrt{3} + 2\sqrt{7} \\ = 1 \sqrt{3} + 2 \sqrt{7} \\ = \sqrt{3} + 2 \sqrt{7} [/tex][tex]d). \sqrt{24} - \sqrt{150} - \sqrt{54} + \sqrt{600} \\ = \sqrt{4.6} - \sqrt{25.6} - \sqrt{9.6} + \sqrt{100.6} \\ = 2 \sqrt{6} - 5 \sqrt{6} - 3 \sqrt{6} + 10 \sqrt{6} \\ = (2 - 5 - 3 + 10) \sqrt{6} \\ = 4 \sqrt{6} [/tex][tex]e). \sqrt{9} + \sqrt{200} - \sqrt{72} \\ = 3 + \sqrt{100.2} - \sqrt{36.2} \\ = 3 + 10 \sqrt{2} - 6 \sqrt{2} \\ = 3 + 4 \sqrt{2} [/tex]](https://id-static.z-dn.net/files/d91/faf9df8d78de71636f7a8d81427a7293.jpg)
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Last Update: Tue, 01 Nov 22