Jawaban:

1.

a. panjang kerangka balok = 4(p+l+t)

= 4(14+6+8) = 4×28 = 112 cm

b. LP balok = 2(pl+pt+lt)

= 2(14×6+14×8+6×8)

= 2(84+112+48)

= 2×244

= 488 cm²

c. V ½ balok = ½×p×l×t

= ½×14×6×8

= 336 cm³

2.

a. panjang kerangka prisma =

= K alas + K tutup + jumlah rusuk tegak

= 2(10+9) + 2(10+4) + 2(12+13)

= 2×19+2×14+2×25

= 38+28+50

= 116 cm

b. LP prisma = 2 × Luas alas + Keliling alas×tinggi

= 2×½×(a+b)×t + (AB+BF+FE+EA) × t

= 2×½×(9+4)×12 + (4+13+9+12) × 10

= 13×12 + 38×10

= 156+380

= 536 cm²

c. V prisma = Luas alas × tinggi

= ½×(a+b)×t × t

= ½×(9+4)×12 × 10

= 13×6×10

= 780 cm³

3.

a. LP limas = luas alas + jumlah luas sisi tegak

= p×l + 2(LABT+LBCT)

= 12×16 + 2(½×12×8 + ½×16×6)

= 192 + 2(48+48)

= 192 + 2×96

= 192+192

= 384 cm²

b. V limas = ⅓×luas alas × tinggi

= ⅓×p×l×t

= ⅓×12×16×18

= 1.152 cm³

4.

a. V = V balok+V kubus

= p×l×t + s³

= 15×12×15 + 12³

= 2700+1728

= 4428 cm³

b. V = V balok + V prisma

= p×l×t + L alas×tinggi

= 20×8×10 + ½×a×t × t

= 1600 + ½×8×3 × 20

= 1600 + 12×20

= 1600 + 240

= 1840 cm³

semoga membantu jadikan jawaban tercerdas yaa