Tolong bantu jawab yah, Nanti aku follow dan kasih 20

Berikut ini adalah pertanyaan dari windy2120 pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Tolong bantu jawab yah, Nanti aku follow dan kasih 20 poin​
Tolong bantu jawab yah, Nanti aku follow dan kasih 20 poin​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

\huge{a.}

\sf Q-R=\left[\begin{array}{ccc}4&0\\1&5\end{array}\right]-\left[\begin{array}{ccc}0&-1\\4&6\end{array}\right]

\sf Q-R=\left[\begin{array}{ccc}4-0&0-(-1)\\1-4&5-6\end{array}\right]=\left[\begin{array}{ccc}4&1\\-3&-1\end{array}\right]

\sf P.(Q-R)=\left[\begin{array}{ccc}3&2\\-1&3\end{array}\right].\left[\begin{array}{ccc}4&1\\-3&-1\end{array}\right]

\sf P.(Q-R)=\left[\begin{array}{ccc}(3\times 4)+(2\times -3)&(3\times 1)+(2\times -1)\\(-1\times 4)+(3\times -3)&(-1\times 1)+(3\times -1)\end{array}\right]

\boxed{\sf P.(Q-R)=\left[\begin{array}{ccc}6&1\\-13&-4\end{array}\right]}

\sf P.Q=\left[\begin{array}{ccc}3&2\\-1&3\end{array}\right].\left[\begin{array}{ccc}4&0\\1&5\end{array}\right]

\sf P.Q=\left[\begin{array}{ccc}(3\times 4)+(2\times 1)&(3\times 0)+(2\times 5)\\(-1\times 4)+(3\times 1)&(-1\times 0)+(3\times 5)\end{array}\right]

\sf P.Q=\left[\begin{array}{ccc}14&10\\-1&15\end{array}\right]

\sf P.R=\left[\begin{array}{ccc}3&2\\-1&3\end{array}\right].\left[\begin{array}{ccc}0&-1\\4&6\end{array}\right]

\sf P.R=\left[\begin{array}{ccc}(3\times 0)+(2\times 4)&(3\times -1)+(2\times 6)\\(-1\times 0)+(3\times 4)&(-1\times -1)+(3\times 6)\end{array}\right]

\sf P.R=\left[\begin{array}{ccc}8&9\\12&19\end{array}\right]

\sf P.Q-P.R=\left[\begin{array}{ccc}14&10\\-1&15\end{array}\right]-\left[\begin{array}{ccc}8&9\\12&19\end{array}\right]

\sf P.Q-P.R=\left[\begin{array}{ccc}14-8&10-9\\-1-12&15-19\end{array}\right]

\boxed{\sf P.Q-P.R=\left[\begin{array}{ccc}6&1\\-13&-4\end{array}\right]}

\boxed{\boxed{\red{\sf P.(Q-R)=P.Q-P.R}}}

\\

\huge{b.}

\sf (P+Q)^T=\left(\left[\begin{array}{ccc}3&2\\-1&3\end{array}\right]+\left[\begin{array}{ccc}4&0\\1&5\end{array}\right]\right)^T

\sf (P+Q)^T=\left[\begin{array}{ccc}3+4&2+0\\-1+1&3+5\end{array}\right]^T

\sf (P+Q)^T=\left[\begin{array}{ccc}7&2\\0&8\end{array}\right]^T

\huge{\sf (P+Q)^T=\left[\begin{array}{ccc}7&0\\2&8\end{array}\right]}

\sf P^T=\left[\begin{array}{ccc}3&2\\-1&3\end{array}\right]^T

\sf P^T=\left[\begin{array}{ccc}3&-1\\2&3\end{array}\right]

\sf Q^T=\left[\begin{array}{ccc}4&0\\1&5\end{array}\right]^T

\sf Q^T=\left[\begin{array}{ccc}4&1\\0&5\end{array}\right]

\sf P^T+Q^T=\left[\begin{array}{ccc}3&-1\\2&3\end{array}\right]+\left[\begin{array}{ccc}4&1\\0&5\end{array}\right]

\sf P^T+Q^T=\left[\begin{array}{ccc}3+4&-1+1\\2+0&3+5\end{array}\right]

\huge{\sf P^T+Q^T=\left[\begin{array}{ccc}7&0\\2&8\end{array}\right]}

\red{\huge{\sf (P+Q)^T=P^T+Q^T}}

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Last Update: Sat, 26 Jun 21