peluang

ruang sampel

4 kartu merah bernomor 1, 2, 3, 4

3 kartu putih bernomor 5, 6, 7

banyak ruang sampel = n(S) = 4 × 3 = 12

x = jumlah pasangan nomor kartu

x = 10 → A = {(3,7) , (4,6)} → n(A) = 2

F(x) = n(A)/n(S)

peluang terambil jumlah 10 = F(10)

F(10) = 2/12 = 1/6

x = 6 → A = {(1,5)} → n(A) = 1

peluang terambil jumlah 6 = F(6)

F(6) = 1/12

x = 9 → A = {(2,7) , (3,6) , (4,5)} → n(A) = 3

peluang terambil jumlah 9 = F(9)

F(9) = 3/12 = 1/4

x = 7 → A = {(1,6) , (2,5)} → n(A) = 2

peluang terambil jumlah 7 = F(7)

F(7) = 2/12 = 1/6

x = 8 → A = {(1,7) , (2,6) , (3,5)} → n(A) = 3

peluang terambil jumlah 8 = F(8)

F(8) = 3/12 = 1/4

Opsi → (2)