A pair of shoes cost $(4x² -9)anda bag cost $ (2x² - 3x + 5 ). Find the total cost of five such pairs of shoes and four of the bags in terms of x.

⇒ The total cost of five such pairs of shoes and four of the bags is $(28x² - 12x - 25).

To solve this problem, you can use multiplication operations in algebra.

Penjelasan dengan langkah-langkah:

Given:

A pair of shoes cost $(4x² -9).

A bag cost $ (2x² - 3x + 5 ).

Question:

Find the total cost of five such pairs of shoes and four of the bags in terms of x.

Solution:

Find the total price for the five shoes.

The total price = The number of shoes × the price for each pair of shoes

The total price = 5 × $(4x² - 9)

The total price = $(20x² - 45)

So, the total price for the five shoes is  $(20x² - 45).

Find the total price for the four bags.

The total price = The number of the bags × the price for each bag

The total price = 4 × $(2x² - 3x + 5 )

The total price = $(8x² - 12x + 20)

So, the total price for the four bags is $(8x² - 12x + 20).

Find the total cost of five such pairs of shoes and four of the bags

The total price = the total price for the five shoes + the total price for the four bags

The total price = $(20x² - 45) + $(8x² - 12x + 20)

The total price = $(20x² + 8x² - 12x - 45 + 20)

The total price = $(28x² - 12x - 25)

So, the total cost of five such pairs of shoes and four of the bags is $(28x² - 12x - 25).

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• the first three terms in geometric progression are (7x-7),(2x + 1),and (x-3) where x is a positive integer.find the value of x and find the sum of the first 5 terms of the progression: yomemimo.com/tugas/15813512

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