Jawab:

Penjelasan dengan langkah-langkah:

2.a. r = √(x²+y²) = 5√2

x²+y² = 50

β = 315° = arctan(y/x)

y/x = tan(315°) = -1

y = -x   => x²+(-x)² = 50

2x² = 50

x = ± 5  => karena β = 315°, maka pilih x = 5 (β berada di kuadran 4 dimana x bernilai positif)

y = -x = -5

P(5√2, 315°) = P(5,-5)

b. β = 240° = arctan(y/x)

y/x = tan(240°) = √3

y = x√3

x²+y² = 8²

x² + (x√3)² = 64

4x² = 64

x = ± 4  (karena β = 240°, maka x bernilai negatif, pilih x = -4)

x = -4  => y = -4√3

Q(8,240°) = Q(-4,-4√3)

c. y/x = tan(60°)  = √3 => y = x√3

60° => x>0, y>0

x²+y² = 6² = 36

x² + (x√3)² = 36

4x² = 36

x = ± 3 = 3

y = 3√3

R(6,60°) = R(3, 3√3)