persiapan uasbn

no. 1

125^1/3 - (1/4)^-1/2 + 16^3/4

= 5^(3 × 1/3) - 2^(-2 × (-1/2)) + 2^(4 × 3/4)

= 5¹ - 2¹ + 2³

= 3 + 8

= 11

no. 2

(3√5 + 2)(4√5 - 7)

= 3√5 (4√5 - 7) + 2(4√5 - 7)

= 60 - 21√5 + 8√5 - 14

= 46 - 13√5

no. 3

cek soal

no. 4

perhatikan kesamaan letak

y = 2x

4x + y = 12

4x + 2x = 12

6x = 12

x = 2

y = 2x = 4

2y - 5x

= 2.4 - 5.2

= -2

no. 5

3x² - 2x - 8 = 0

(3x + 4)(x - 2) = 0

x = -4/3 atau x = 2

1/x1 + 1/x2

= 1/(-4/3) + 1/2

= -3/4 + 1/2

= -1/4

no. 6

tampung 3 = a

tampung 2 = b

3a + 2b = 104

a + b = 42

eliminasi substitusi

a = 20 kamar

b = 22 kamar

berdaya tampung 3 = 20 kamar

no. 7

2x - y = 8

x + 2y = 4

x + 2(2x - 8) = 4

5x - 16 = 4

5x = 20

x = 4

y = 2x - 8

y = 8 - 8

y = 0

xy = 4 . 0 = 0

no. 8

pelajari perkalian matriks

jawaban : E