Jawaban:

Suku Banyak

Polinomial

Penjelasan dengan langkah-langkah:

P(x)=S(x)

x²-3x+2

(x-2)(x-1)=0

(x-2)=0 / (x-1)=0

(x)=2 = (x)=1

P(x)=(x²-x-6)(ax+b)+(8x-10)

S(x)=(4x-6)

P(2)=(2²-2-6)(a(2)+b)+(8(2)-10)

=(4-8)(2a+b)+(16-10)

=(-4)(2a+b)+(6)

=(-8a-4b)+6

=-8a-4b+6

S(2)=4(2)-6

=8-6

=2

P(2)=S(2)

-8a-4b+6=2

-8a-4b=2-6

-8a-4b=-4......(1)

P(1)=(1²-1-6)(a(1)+b)+(8(1)-10)

=(1-7)(a+b)+(8-10)

=-6(a+b)+(-2)

=-6a-6b-2

S(1)=4(1)-6

=4-6

=-2

P(1)=S(1)

-6a-6b-2=-2

-6a-6b=-2+2

-6a-6b=0 ....(2)

-8a-4b=-4 x 3 .....(1)

-6a-6b=0 x 2 .....(2)

-24a-12b=-12

-12a-12b=0 -

-12a =-12

a =-12/-12

a =1

-8a-4b=-4

-8(1)-4b=-4

-8-4b=-4

-4b=-4+8

-4b=4

b=4/-4

b=-1

P(x)=(x²-x-6)(ax+b)+(8x-10)

=(x²-x-6)(1(x)+(-1)+(8x-10)

=(x²-x-6)(x-1)+(8x-10)

=(x³-x²-6x-x²+x+6)+(8x-10)

=(x³-2x²-5x+6)+(8x-10)

=(x³-2x²+3x-4)

⇔Opsi A

Detail Jawaban:

Mapel : Matematika

Kelas : 11 / XI SMA

Materi : Suku Banyak ( Polinomial )

Kode Kategorisasi : -

Kata Kunci : Suku Banyak ( Polinomial )

Demikian

Semoga membantu dan bermanfaat!