d. 6 & 5

Penjelasan dengan langkah-langkah :

Fungsi : f(x) = ax² + bx + 1

Turunan : f′(x) = 2ax²⁻¹ + b(1) + 0

                 f′(x) = 2ax¹ + b + 0

                 f′(x) = 2ax + b

- Buat model matematika

f′(x) = 2ax + b

f′(0) = (2)(0)a + b → 0a + b = 5 … pers (1)

f′(2) = (2)(2)a + b → 4a + b = 29 … pers (2)

- Eliminasi variabel b

0a + b = 5

4a + b = 29

__________ -

-4a = -24

    a = -24 ÷ (-4)

    a = 6

- Substitusi a ke pers (2)

  4a + b = 29

4(6) + b = 29

  24 + b = 29

          b = 29 - 24

          b = 5