Jawaban:

bisa!

(π/3)·(4+2√3) satuan ✅

atau 7,82 satuan

Penjelasan dengan langkah-langkah:

L₁ = (x-2)² + (y-5)² = 4

artinya r = √4 = 2, titik tengah lingkaran = (2, 5)

L₂ = (x-2)² + (y-1)² = 12

artinya r = √12, titik tengah lingkaran = (2, 1)

Cari titik potong dua lingkaran.

(i) Cari y

Kurangi rumus kedua lingkaran

(x-2)² + (y-5)² = 4

(x-2)² + (y-1)² = 12

______________-

hasilnya

(x-2)² + (y-5)² - ((x-2)² + (y-1)²) = 4-12

(x-2)(x-2) + (y-5)(y-5) - ((x-2)(x-2) + (y-1)(y-1)) = -8

x²-2x-2x+4+y²-5y-5y+25 - (x²-2x-2x+4 + y²-y-y+1) = -8

x²-4x+4+y²-10y+25 - (x²-4x+4 + y²-2y+1) = -8

x²-4x+4+y²-10y+25 - x²+4x-4-y²+2y-1 = -8

Coret yang ditebalkan =

-10y+25+2y-1 = -8

-8y+24 = -8

-8y = -8-24

-8y = -32

y = 32/8

y = 4