Jawab:

Penjelasan dengan langkah-langkah:

Jawab:

Penjelasan dengan langkah-langkah:

Rumus = y-y1/y2-y1=x-x1/x2-x1

1. x1= -7   x2= 5

   y1=4    y2= -3

y-y1/y2-y1=x-x1/x2-x1

y-4/ -3-4=x-(-7)/5-(-7)

y-4/-7=x+7/12

12y-48=-7x-49

12y= -7x-1 :12

y=-7/12x+1/12

2. x1= 4  x2= -6

   y1= -2    y2= -12

y-y1/y2-y1=x-x1/x2-x1

y-2/ -12-(-2)=x-4/-6-4

y-2/-10=x-4/-10

-10y+20=-10x+40

-10y= -10x+20 :10

-y=-x+2

y=x-2

3. x1= -10  x2= -2

   y1= -7    y2= 5

y-y1/y2-y1=x-x1/x2-x1

y-(-7)/5-(-7)=x-(-10)/-2-(-10)

y+7/12=x+10/8

8y+65=12x+120

8y= 12x+64 :8

y=3/2x+8

4. x1= 9  x2= 0

   y1= 0    y2= -11

y-y1/y2-y1=x-x1/x2-x1

y-0/-11- 0=x-9/0-9

y/-11=x-9/-9

-9y=-11x+99

-9y= -11x+99 :9

-y=-1 1/3x+10

y= 1 1/3x-10

5. x1= -15  x2= 0

   y1= 0    y2= -8

y-y1/y2-y1=x-x1/x2-x1

y-0/-8- 0=x-(-15)/0-(-15)

y/-8=x+15/15

15y=-8x-120

15y= -8x+120 :15

y=-8/15x+8