Penyelesaian :

1) Volume tabung = π x r x r x t

770 = 22/7 x r x r x 5

770 = 110/7 x r x r

770 : 110/7 = r x r

770 x 7/110 = r x r

5.390/110 = r x r

49 = r x r

√49 = r

r = 7

2) Tinggi = 3 × volume/alas

Tinggi = 3 × 256cm³ /48cm²

Tinggi = 16 cm

Jadi, tinggi limas tersebut adalah 16 cm

3) Volume = 38.808cm³

= 22/7

r = 3√(3v/4π)

r = 3√(3(38.808cm³)/4(22/7))

r = 3√116.424cm³/4(22/7))

r = 3√116.424cm³/(88/7))

r = 3√(116.424cm³x 7)/88

r = 3√(814.968cm³)/88)

r = 3√9261cm³

r = 21cm

4) Volume = ⅓ × π × r × r × t

V = ⅓ × 22/7 × 14 × 14 × 18

V = 22 × 2 × 14 × 6

V = 3.696cm³

5) Tabung = 22/7 x 7 x 7 x 6 = 924cm³

Kerucut = 1/3 x 22/7 x 7 x 7 x 12 = 616cm³

924 + 616 = 1540cm³

6) Mempunyai 5 Titik sudut

7) Bangun Limas Segitiga dan memiliki 4 buah titik sudut.

8) Limas Segi Empat

9) V = (1/2 x a x t) x tinggi prisma

V = (1/2 × 4 × 5 ) × 12

V = (2 × 5 ) × 12

V = 10 × 12

V = 120cm³

10) Volume = π × r × r × t

V = 3,14 × 10 × 10 × 30

V = 314 × 30

V = 9.420cm³

Semoga Membantu

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