Berikut ini adalah pertanyaan dari noviankivianki pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas
kelas:10
note:semoga yang jawab bener bener orang pintar kalau ngasal ya terima sendiri akibatnya tapi aku tidak mendoakan.
![nomor 1 -5 tugas kognitif mapel:MTK minatkelas:10note:semoga yang jawab bener bener orang pintar kalau ngasal ya terima sendiri akibatnya tapi aku tidak mendoakan.](https://id-static.z-dn.net/files/ddd/da3d65b1adf46da64dd2a5a9c8a20730.jpg)
Jawaban dan Penjelasan
Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.
1.
log (x+6) = 2 log x
log (x+6) = log x²
x+6 = x²
0 = x² - x - 6
0 = (x-3)(x+2)
x-3 =0 dan x+2= 0
x = 3 dan x = -2
Hp = {-2,3}
2.
log (3x+4) = log (x-2) + log 4
log (3x+4) = log (x-2) . 4
log (3x+4) = log (4x-8)
3x+4 = 4x-8
3x-4x = -8-4
-x = -12
x = 12
Hp = { 12 }
3.
log x - log 2 = log 16
log (x/2) = log 16
x/2 = 16
x = 32
Hp = { 32 }
4.
log (x+1) - log (x-1) = log 3
log (x+1) = log 3 + log (x-1)
log (x+1) = log 3.(x-1)
x+1 = 3x-3
x-3x = -3-1
-2x = -4
x = 2
Hp = { 2 }
5.
³log 2 + ³log(x+4) = 2
³log 2.(x+4) = ³log3²
³log(2x+8) = ³log9
2x + 8 = 9
2x = 9-8
2x = 1
x = 1/2
Hp = { 1/2 }
![1.log (x+6) = 2 log xlog (x+6) = log x²x+6 = x²0 = x² - x - 60 = (x-3)(x+2)x-3 =0 dan x+2= 0x = 3 dan x = -2Hp = {-2,3}2.log (3x+4) = log (x-2) + log 4log (3x+4) = log (x-2) . 4log (3x+4) = log (4x-8)3x+4 = 4x-83x-4x = -8-4-x = -12x = 12Hp = { 12 }3.log x - log 2 = log 16log (x/2) = log 16x/2 = 16x = 32Hp = { 32 }4.log (x+1) - log (x-1) = log 3log (x+1) = log 3 + log (x-1)log (x+1) = log 3.(x-1)x+1 = 3x-3x-3x = -3-1-2x = -4x = 2Hp = { 2 }5.³log 2 + ³log(x+4) = 2³log 2.(x+4) = ³log3²³log(2x+8) = ³log92x + 8 = 92x = 9-82x = 1x = 1/2Hp = { 1/2 }](https://id-static.z-dn.net/files/dbc/046bc462d55b5c0433f3c2487f25bff4.jpg)
![1.log (x+6) = 2 log xlog (x+6) = log x²x+6 = x²0 = x² - x - 60 = (x-3)(x+2)x-3 =0 dan x+2= 0x = 3 dan x = -2Hp = {-2,3}2.log (3x+4) = log (x-2) + log 4log (3x+4) = log (x-2) . 4log (3x+4) = log (4x-8)3x+4 = 4x-83x-4x = -8-4-x = -12x = 12Hp = { 12 }3.log x - log 2 = log 16log (x/2) = log 16x/2 = 16x = 32Hp = { 32 }4.log (x+1) - log (x-1) = log 3log (x+1) = log 3 + log (x-1)log (x+1) = log 3.(x-1)x+1 = 3x-3x-3x = -3-1-2x = -4x = 2Hp = { 2 }5.³log 2 + ³log(x+4) = 2³log 2.(x+4) = ³log3²³log(2x+8) = ³log92x + 8 = 92x = 9-82x = 1x = 1/2Hp = { 1/2 }](https://id-static.z-dn.net/files/d50/00852284166540201e2ec0f7671b1ae3.jpg)
![1.log (x+6) = 2 log xlog (x+6) = log x²x+6 = x²0 = x² - x - 60 = (x-3)(x+2)x-3 =0 dan x+2= 0x = 3 dan x = -2Hp = {-2,3}2.log (3x+4) = log (x-2) + log 4log (3x+4) = log (x-2) . 4log (3x+4) = log (4x-8)3x+4 = 4x-83x-4x = -8-4-x = -12x = 12Hp = { 12 }3.log x - log 2 = log 16log (x/2) = log 16x/2 = 16x = 32Hp = { 32 }4.log (x+1) - log (x-1) = log 3log (x+1) = log 3 + log (x-1)log (x+1) = log 3.(x-1)x+1 = 3x-3x-3x = -3-1-2x = -4x = 2Hp = { 2 }5.³log 2 + ³log(x+4) = 2³log 2.(x+4) = ³log3²³log(2x+8) = ³log92x + 8 = 92x = 9-82x = 1x = 1/2Hp = { 1/2 }](https://id-static.z-dn.net/files/df6/4b4f7c651bef36fb3233049048343ef8.jpg)
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Last Update: Tue, 15 Feb 22