Tolong jawab akan ya​

Berikut ini adalah pertanyaan dari aqeelacalisa pada mata pelajaran Matematika untuk jenjang Sekolah Menengah Atas

Tolong jawab akan ya​
Tolong jawab akan ya​

Jawaban dan Penjelasan

Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.

Sifat-sifat perpangkatan:

\boxed{\begin{array}{c}{\rm {a}^{m}\times{a}^{n}={a}^{m+n}}\\\rm {a}^{m}\div{a}^{n}={a}^{m-n}\\\rm {({a}^{m})}^{n}={a}^{m\times n}\\\rm {a}^{\frac{m}{n}}=\sqrt[n]{{a}^{m}}\\\rm {a}^{-m}=\frac{1}{{a}^{m}}\\\rm {(\frac{a}{b})}^{-m}={(\frac{b}{a})}^{m}\\\rm {(\frac{a}{b})}^{m}=\frac{{a}^{m}}{{b}^{m}}\end{array}}

Jawaban:

 \sqrt[3]{ {3}^{5} } \times \sqrt[3]{ {3}^{4} } + \sqrt[3]{ - 27 \times 8}

 = {3}^{ \frac{5}{3} } \times {3}^{ \frac{4}{3} } + \sqrt[3]{ - 216}

 = {3}^{ \frac{5}{3} + \frac{4}{3} } + ( - 6)

 = {3}^{ \frac{9}{3} } - 6

 = {3}^{3} - 6

 = 27 - 6

=\bf \color{red}{21}

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Last Update: Thu, 13 Jan 22