Penjelasan dengan langkah-langkah:

garis b melalui titik

(0, 5) dan (1,2)

gradien garis b

m = (2 - 5)/(1- 0)

m = -3

persamaan garis b

y - b = m(x - a)

ambil titik (1, 2)

y - 2 = -3(x - 1)

y = -3x + 3 + 2

y = -3x + 5

3x + y - 5 = 0..........(1)

garis a melalui titik

(-1, -3) dan (5, 1)

gradien garis b

m = (1 + 3)/(5 + 1)

m = 4/6

m = 2/3

persamaan garis a

y - b = m(x - a)

ambil titik (5, 1)

y - 1 = 2/3(x - 5)

3(y - 1) = 2(x - 5)

3y - 3 = 2x - 10

3y = 2x - 10 + 3

3y = 2x - 7

2x - 3y - 7 = 0..........(2)

eliminasi (1) dan (2)

3x + y - 5 = 0........(x 3)

2x - 3y - 7 = 0.......(x 1)

9x + 3y - 15 = 0

2x - 3y - 7 = 0

----------------------- +

11x - 12 = 0

11x = 12

x = 2

2x - 3y - 7 = 0

2(2) - 3y - 7 = 0

3y = 4 - 7

3y = -3

y = -1

jadi titik potongnya = (2, -1)