Jawaban:

xy²z³ atau x,y,z = 1, 2, -1

2. x,y,z = -1, -2, 1

Penjelasan dengan langkah-langkah:

1. [xy+xz-yz = 3] - [xy-xz+yz = 1 ]

2xz - 2yz = 2 ...(1)

2. [xy-2xz-yz = 6 ] - [xy-xz+yz = 1 ]

-xz - 2yz = 5

xz + 2yz = -5 …(2)

3. [2xz - 2yz = 2] + [xz + 2yz = -5]

3xz = -3

xz = -1

z = -1/x ...(3)

4. xz + 2yz = -5

-1 + 2yz = -5

2yz = -4

yz = -2

5. (xz / yz) = (-1 / -2)

(x/y) = (1/2)

y = 2x...(4)

6. xy + xz - yz = 3

x(2x) + x(-1/x) - (2x)(-1/x) = 3

2x² - 1 + 2 = 3

2x² - 2 = 0

x²-1 = 0

(x-1)(x+1) = 0

x₁ = 1 v x₂ = -1

7. y = 2x

y₁ = 2(1) = 2 v y₂ = 2(-1) = -2

8. z = (-1/x)

z₁ = (-1/1) = -1 v z₂ = (-1/-1) = 1

semoga benar!!