Penjelasan dengan langkah-langkah:

misalkan

maka

4a - 3b = 1 ...(1

5b + 3c = 8 ...(2

3a + b + 2c = 6 ...(3

nyatakan b dalam a pada persamaan 1.

4a - 3b = 1

4a = 1 + 3b

a = (1 + 3b)/4 ...(4

subs. pers 4 ke 3

3/4 x (1 + 3b) + b + 2c = 6

3/4 + 9/4 b + b + 2c = 6

(3 + 9b + 4b + 8c)/4 = 6

3 + 9b + 4b + 8c = 24

13b + 8c = 21 ...(5

eliminasi pers 5 dan 2

5b + 3c = 8 |x8| 40b + 24c = 64

13b + 8c = 21 |x3| 36b + 24c = 63 -

4b = 1

b = 1/4 ...(6

subs. 6 ke 2

5(1/4) + 3c = 8

5/4 + 3c = 8

3c = (32-5)/4

3c = 27/4

c = 27/4 x 1/3

c = 27/12 ...(7

masukkan 6 dan 7 ke 3

3a + 1/4 + 2 x 27/12 = 6

3a + 1/4 + 27/6 = 6

3a = 6 - 1/4 - 27/6

3a = (72 - 3 - 54)/12

3a = 15/12

a = 15/12 x 1/3

a = 5/12

a= 5/12

1/(x - 1) = 5/12

5 (x -1) = 12

5x - 5 = 12

5x = 17

x = 17/5

b = 1/4

1/(y - 2) = 1/4

1(y - 2) = 4

y - 2 = 4

y = 6

c = 27/12

1/(z - 3) = 27/12

27(z - 3) = 12

27z - 81 = 12

27z = 93

z = 93/27

2x - y + z

= 2 x 17/5 - 6 + 93/27

= 34/5 - 6 + 93/27

= (918 - 810 + 465)/135

= 573/135

= 4.23

= 4

jawabanku kok 4 ya lur...