~Soal:

1. Hasil dari (64)^(-1/3) + (√49) – (1/8)⁰ adalah...

2. Sederhanakan hasil operasi bilangan

berpangkat (2p³q^(-4)³ × (4p²q⁸) .

3. Sederhanakan hasil penjumlahan bentuk akar dari √175 + 4√7 – √63 .

~Jawab:

1. 64^(-1/3) + (√49) – (1/8)⁰

= 1/64^(-1/3) + (√7²) – 1

= 1/(2⁶)^(-1/3) + 7 – 1

= 1/2^(6 × (-1/3)) + 6

= 1/2² + 6

= 1/4 + 6/1

= 1/4 + 24/4

= 25/4

= 6 1/4 ✓

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2. (2p³q^(-4)³ × (4p²q⁸)

= 2³ (p³)³ q^(-4)³ × 4p²q⁸

= 8p^(3 × 3) q^(-4 × 3) × 4p²q⁸

= 8p⁹q^(-12) × 4p²q⁸

= (8 × 4)p^(9 + 2) q^(-12 + 8)

= 32p¹¹q^(-4) ✓

→ Bentuk positifnya:

= 32p¹¹q^(-4)

= 32p¹¹ × 1/q⁴

= 32p¹¹/q⁴ ✓

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3. √175 + 4√7 – √63

= √(5² × 7) + 4√7 – √(3² × 7)

= 5√7 + 4√7 – 3√7

= (5 + 4 – 3)√7

= 6√7 ✓

~Kesimpulan:

∴ Jadi, hasil dari soal tersebut adalah 1. {6 1/4}, 2. {32p¹¹q^(-4)}, 3. {6√7}.

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