Penjelasan dengan langkah-langkah:

1. f(x) = 3x - x³

dikatakan fungsi naik jika f'(x) > 0

3 - 3x² > 0

1 - x² > o

(1 - x)(1 + x)>0

pakai garis bilangan

---------- +++++++ -------

.............o................o...........

-1 1

kurva f(x) = 3x - x³ akan naik pada interval -1 < x <1

2. y= 3x²-5x+4

y' = 3(2)x^2-1 - 5(1) x^1-1

y' = 6x -5

3. f(x) = (-x + 2)³

f'(x) = 3(-x + 2)² . (-1)

f'(x) = -3(-x + 2)²

f"(x) = -6(-x + 2) . (-1)

f"(x) = 6(-x + 2)

f'(4) = -3(-4 + 2)²

f'(4) = -3 . 4

f'(4) = -12

f"(1) = 6(-1 + 2)

f"(1) = 6

f'(4) - f"(1) = -12 - 6

f'(4) - f"(1) = -18

Semoga membantu :)