1. 2x² + 6x -7=0 akar-akarnya α dan β

α + β = -b/a = -6/2 = -3

α.β = c/a = -7/2

Persamaan kuadrat baru akar-akarnya α-2 dan β-2 maka

(α-2)+ (β-2) = (α+β)-4 = -3-4=-7

(α-2)(β-2)= αβ-2(α+β) + 4 = -7/2 -2(-3) +4 = 13/2

persaman kuadrat baru

x² -(hasil jumlah)x + hasil kali=0

x² -(-7)x +13/2 =0

2x² + 14x +13=0

2. 3x²-6x + 2=0

α+β = -b/a = -(-6)/2= 3

α.β = c/a= 2/3

α-β = √D/a = akar (b²-4ac) /a = akar ((-6)²-4.3.2)/3= (√12)/3

a. (α-β)² =((√12)/3)= 12/9 = 4/3

b. 1/α + 1/β = (α+β)/(αβ) = 3/(2/3)= 9/2