I don't know those guy's but somehow they gimme a place to sit on my way

Penjelasan dengan langkah-langkah:

misal 1/x = a; 1/y = b; 1/z = c

maka

3a + 4b - c = -2 ...(1

a - 2b + 3c = 6 ...(2

2a + 6b + c = -3 ...(3

eliminasi c pada 1 dan 3

3a + 4b - c = -2

2a + 6b + c = -3 +

5a + 10b = -5 ...(4

eliminasi c pada 2 dan 3

a - 2b + 3c = 6 |x 1| a - 2b + 3c = 6

2a + 6b + c = -3 |x3| 6a + 18b + 3c = -9 _

-5a - 20b = 15 ...(5

eliminasi a pada 4 dan 5

5a + 10b = -5

-5a - 20b = 15 +

10b = 10

b = -10/10

b = -1 ...(6

masukkan 6 ke 4

5a + 10b = -5

5a + 10(-1) = -5

5a - 10 = -5

5a = -5 + 10

5a = 5

a = 15/5

a = 3 ...(7

masukkan 6 dan 7 ke 1

3a + 4b - c = -2

3(3) + 4(-1) - c = -2

9 - 4 - c = -2

5 - c = -2

5 + 2 = c

7 = c

a = 1/x

x = 1/a

x = 1/3

b = 1/y

y = 1/-1

y = -1

c = 1/z

z = 1/c

z = 1/7