T A I K ( TOLONG AKU IYA KAK ) #NO NGASAL#NO AMBIL POINT#NO BAHASA ALIEN#NO SPAM KOMENTAR #PAKE CARA#NOMOR A DAN C

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T A I K ( TOLONG AKU IYA KAK ) #NO NGASAL#NO AMBIL POINT#NO BAHASA ALIEN#NO SPAM KOMENTAR #PAKE CARA#NOMOR A DAN C​

tantosuyanto · Accepted Answer

Jawab:(1a.) ≈ 94 cm(1b.) ≈ 64,26 cm(1c.) ≈ 54 cm(1d.) ≈ 71,4 cmPenjelasan dengan langkah-langkah:Keliling lingkaran =2×π×rdimana r = jari-jari(atau)π×ddimana d = diametermaka(1a) Keliling = [(3/4)×keliling lingkaran] + 2×jari-jariKeliling = ((3/4)×(2×π×r)) + (2×r)r = 14 cm, makaKeliling = ((3/4)×2×π×14) + (2×14)Keliling = ((6/4)×π×14) + 28Keliling = ((84/4)×π) + 28Keliling = (21×π) + 28π ≈ 22/7 makaKeliling ≈ (21×(22/7)) + 28Keliling ≈ 66 + 28≈ 94 cm(1b) Keliling = [(1/4)×keliling lingkaran] + 2×jari-jariKeliling = ((1/4)×(2×π×r)) + (2×r)r = 18 cm, makaKeliling = ((1/4)×2×π×18) + (2×18)Keliling = ((1/2)×π×18) + 36Keliling = (9×π) + 36π ≈ 3,14 makaKeliling ≈ (9×3,14) + 36Keliling ≈ 28,26 + 36≈ 64,26 cm(1c) Keliling = [(1/2)×keliling lingkaran] + diameterKeliling = ((1/2)×(π×d)) + dd = 21 cm, makaKeliling = ((1/2)×π×21) + 21π ≈ 22/7 makaKeliling ≈ ((1/2)×(22/7)×21) + 21Keliling ≈ ((1/2)×66) + 21Keliling ≈ 33 + 21≈ 54 cm(1d) Keliling = [(1/4)×keliling lingkaran] + 2×jari-jariKeliling = ((1/4)×(2×π×r)) + (2×r)r = 20 cm, makaKeliling = ((1/4)×2×π×20) + (2×20)Keliling = ((1/2)×π×20) + 40Keliling = (10×π) + 40π ≈ 3,14 makaKeliling ≈ (10×3,14) + 40Keliling ≈ 31,4 + 40≈ 71,4 cm- jiazheng -

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