Jawaban:

Limit Trigonometri

Penjelasan dengan langkah-langkah:

lim ₓ→₂π/₃ (sin² x)²

(cos 2x)²

(sin²x) (sin²x)

(cos 2x) (cos 2x)

(1-Cos²x)(1-Cos²x)

(cos 2x)(cos 2x)

(1²- Cos²x-Cos²x+Cos⁴x)

(2 Cos²x-1)(2 Cos²x-1)

(1 - 2Cos²x+Cos⁴x)

(4 Cos⁴x-2Cos²x-2Cos²x+1)

(1-2Cos²x+Cos⁴x)

(4 Cos⁴x-4 Cos²x+1)

(1-2Cos(2π/3) Cos(2π/3)+

Cos(2π/3) Cos(2π/3) Cos(2π/3) Cos(2π/3)

(4(Cos(2π/3)Cos(2π/3)Cos(2π/3)Cos(2π/3)

-4(Cos (2π/3)Cos (2π/3)+1)

(1-2Cos(120) Cos(120) +

(Cos120 Cos120 Cos120 Cos120)

(4(Cos120 Cos120 Cos120 Cos120) -

4(Cos 120 Cos 120)+1)

(1-2(-1/2) (-1/2) + (-1/2)(-1/2)(-1/2)(-1/2)

( 4(-1/2)(-1/2)(-1/2)(-1/2) - 4(-1/2)(-1/2)+1)

(1-2(1/4) + (1/4)(1/4)

( 4(1/4)(1/4) - 4(1/4)+1)

(1-2/4) + (1/16)

(4(1/16)-1+1)

(1/2) + (1/16)

(4/16+0)

(8/16) + (1/16)

(4/16)

(9/16)

(4/16)

(9/16)x(16/4)

(9/4)

(2 1/4)

Detail Jawaban

Mapel: Matematika

Kelas: X / 10 SMA

Materi: Limit Trigonometri

Kode Kategorisasi:-

Kata Kunci: Limit Trigonometri

Demikian

Semoga membantu dan bermanfaat!