Berikut ini adalah pertanyaan dari DhilaSafana pada mata pelajaran Matematika untuk jenjang Sekolah Dasar
Palai cara yamisalnya no 1 itu memakai cara sehingga tepat dengan jawaban tersebut
gitu ya
![palai cara ya misalnya no 1 itu memakai cara sehingga tepat dengan jawaban tersebut gitu ya](https://id-static.z-dn.net/files/d4d/bb44ff1158f84d52b5d5693202de081a.jpg)
gitu ya
![palai cara ya misalnya no 1 itu memakai cara sehingga tepat dengan jawaban tersebut gitu ya](https://id-static.z-dn.net/files/d4d/bb44ff1158f84d52b5d5693202de081a.jpg)
Jawaban dan Penjelasan
Berikut ini adalah pilihan jawaban terbaik dari pertanyaan diatas.
Jawaban:
2. c
3. a
4. d
5. c
6. a
semoga membantu
![Jawaban:[tex]1) \frac{1}{2} \times 50\% \\ = \frac{1}{2} \times \frac{50}{100} \\ = \frac{50}{200} \\ = \frac{1}{4} (b)[/tex][tex]2) \frac{5}{6} \div 0,14 \\ = \frac{5}{6} \div \frac{14}{100} \\ = \frac{5}{6} \times \frac{100}{14} \\ = \frac{500}{84} \\ = \frac{125}{21} \\ = 5 \frac{20}{21} (d)[/tex][tex]3)0,3 \times \frac{15}{20} \times 80\% \\ = \frac{3}{10} \times \frac{15}{20} \times \frac{80}{100} \\ = \frac{3600}{20.000} \\ = \frac{36}{200} \\ = \frac{9}{50} \\ = 0,18(a)[/tex][tex]4)5 \frac{3}{4} \times 4 \\ = \frac{23}{4} \times \frac{4}{1} \\ = \frac{92}{4} \\ = \frac{23}{1} \\ = 23(d)[/tex][tex]5) (\frac{1}{3} \times 2) + (\frac{3}{4} \times 3) \\ = (\frac{1}{3} \times \frac{2}{1} ) + ( \frac{3}{4} \times \frac{3}{1} ) \\ = \frac{2}{3} + \frac{9}{4} \\ = \frac{8}{12} + \frac{27}{12} \\ = \frac{35}{12} \\ = 2 \frac{11}{12} (c)[/tex][tex]6) \frac{2}{6} \times 0,75 \\ = \frac{2}{6} \times \frac{75}{100} \\ = \frac{150}{600} \\ = \frac{1}{4} (a)[/tex]](https://id-static.z-dn.net/files/df7/f94f1097c602476d192a93a75c019b19.jpg)
![Jawaban:[tex]1) \frac{1}{2} \times 50\% \\ = \frac{1}{2} \times \frac{50}{100} \\ = \frac{50}{200} \\ = \frac{1}{4} (b)[/tex][tex]2) \frac{5}{6} \div 0,14 \\ = \frac{5}{6} \div \frac{14}{100} \\ = \frac{5}{6} \times \frac{100}{14} \\ = \frac{500}{84} \\ = \frac{125}{21} \\ = 5 \frac{20}{21} (d)[/tex][tex]3)0,3 \times \frac{15}{20} \times 80\% \\ = \frac{3}{10} \times \frac{15}{20} \times \frac{80}{100} \\ = \frac{3600}{20.000} \\ = \frac{36}{200} \\ = \frac{9}{50} \\ = 0,18(a)[/tex][tex]4)5 \frac{3}{4} \times 4 \\ = \frac{23}{4} \times \frac{4}{1} \\ = \frac{92}{4} \\ = \frac{23}{1} \\ = 23(d)[/tex][tex]5) (\frac{1}{3} \times 2) + (\frac{3}{4} \times 3) \\ = (\frac{1}{3} \times \frac{2}{1} ) + ( \frac{3}{4} \times \frac{3}{1} ) \\ = \frac{2}{3} + \frac{9}{4} \\ = \frac{8}{12} + \frac{27}{12} \\ = \frac{35}{12} \\ = 2 \frac{11}{12} (c)[/tex][tex]6) \frac{2}{6} \times 0,75 \\ = \frac{2}{6} \times \frac{75}{100} \\ = \frac{150}{600} \\ = \frac{1}{4} (a)[/tex]](https://id-static.z-dn.net/files/ddd/531d1d2421642d7bcba6cccaa2f9a860.jpg)
![Jawaban:[tex]1) \frac{1}{2} \times 50\% \\ = \frac{1}{2} \times \frac{50}{100} \\ = \frac{50}{200} \\ = \frac{1}{4} (b)[/tex][tex]2) \frac{5}{6} \div 0,14 \\ = \frac{5}{6} \div \frac{14}{100} \\ = \frac{5}{6} \times \frac{100}{14} \\ = \frac{500}{84} \\ = \frac{125}{21} \\ = 5 \frac{20}{21} (d)[/tex][tex]3)0,3 \times \frac{15}{20} \times 80\% \\ = \frac{3}{10} \times \frac{15}{20} \times \frac{80}{100} \\ = \frac{3600}{20.000} \\ = \frac{36}{200} \\ = \frac{9}{50} \\ = 0,18(a)[/tex][tex]4)5 \frac{3}{4} \times 4 \\ = \frac{23}{4} \times \frac{4}{1} \\ = \frac{92}{4} \\ = \frac{23}{1} \\ = 23(d)[/tex][tex]5) (\frac{1}{3} \times 2) + (\frac{3}{4} \times 3) \\ = (\frac{1}{3} \times \frac{2}{1} ) + ( \frac{3}{4} \times \frac{3}{1} ) \\ = \frac{2}{3} + \frac{9}{4} \\ = \frac{8}{12} + \frac{27}{12} \\ = \frac{35}{12} \\ = 2 \frac{11}{12} (c)[/tex][tex]6) \frac{2}{6} \times 0,75 \\ = \frac{2}{6} \times \frac{75}{100} \\ = \frac{150}{600} \\ = \frac{1}{4} (a)[/tex]](https://id-static.z-dn.net/files/dda/2a2df25e90ae6aab303a2cd8a29eac2f.jpg)
Semoga dengan pertanyaan yang sudah terjawab oleh Jofia11 dapat membantu memudahkan mengerjakan soal, tugas dan PR sekolah kalian.
Apabila terdapat kesalahan dalam mengerjakan soal, silahkan koreksi jawaban dengan mengirimkan email ke yomemimo.com melalui halaman Contact
Last Update: Sun, 11 Dec 22