Jawaban:

No.1

Diket:

D = 20 cm

D ÷ 2 = r

20 ÷ 2 = 10 cm

Tinggi = 24 cm

Tentukan:

Volume Gabungan?

Jawaban:

Vtabung + V½bola

= ( πr²t ) + ( ½ × 4/3 × πr³ )

= ( 3,14 × 10² × 24 ) + ( ½ × 4/3 × 3,14 × 10³ )

= ( 31,4 × 240 ) + ( 4/3 × 3,14 × 5 × 10 × 10 )

= 7.536 + ( 4/3 × 15,7 × 100 )

= 7.536 + ( 4/3 × 1.570 )

= 7.536 + ( 6.280 ÷ 3 )

= 7.536 + 2.093,3

= 9.629,3 cm³

No.2

Diket:

D = 21 cn

D ÷ 2 = r

21 ÷ 2 = 10,5 cm

Tinggi tabung = 15 cm

Tinggi Kerucut = 40 - 15 = 25 cm

Tentukan:

Volume Gabungan?

Jawaban:

Vtabung + Vkerucut

= ( πr²t ) + ( ⅓ × πr²t )

= ( 22/7 × 10,5² × 15 ) + ( ⅓ × 22/7 × 10,5² × 25 )

= ( 33 × 157,5 ) + ( ⅓ × 33 × 262,5 )

= 5.197,5 + ( 11 × 262,5 )

= 5.197,5 + 2.887,5

= 8.085 cm³